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Phantasy [73]
2 years ago
5

A 6.0M solution HCl is diluted to 1.0M How many milliliters of the 6.0M solution would be used to prepare 100.o mL of the dilute

d 1.0M solution ?
Chemistry
2 answers:
Margarita [4]2 years ago
4 0
Wats r is the most soluble object ever. It is dense
fgiga [73]2 years ago
3 0

Answer:

The answer to your question is  Volume 1 = 16.7 ml

Explanation:

Data

[HCl] 1 = 6.0 M

Volume 1 = ?

[HCl] 2 = 1.0 M

Volume 2 = 100 ml

Process

To solve this problem use the dilution formula

             [HCl] 1 x Volume 1 = [HCl] 2 x Volume 2

-Solve for Volume 1

             Volume 1 = [HCl] 2 x Volume 2 / [HCl] 1

-Substitution

             Volume 1 = 1 x 100 / 6

-Simplification

             Volume 1 = 100/6

-Result

             Volume 1 = 16.7 ml

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How many grams of Boron can be obtained from 234 grams of B2O3?
Xelga [282]

Answer:

72.67g of B

Explanation:

The reaction of B₂O₃ to produce boron (B), is:

B₂O₃ → 3/2O₂ + 2B

<em>That means B₂O₃ produce 2 moles of boron</em>

Molar mass of B₂O₃ is 69.62g/mol. 234g of B₂O₃ contains:

234g B₂O₃ ₓ (1mol / 69.62g) = 3.361 moles of B₂O₃.

As 1 mole of B₂O₃ produce 2 moles of B, Moles of B that can be produced from B₂O₃ is:

3.361mol B₂O₃ ₓ 2 = <em>6.722 moles of B</em>.

As molar mass of B is 10.811g/mol. Thus mass of B that can be produced is:

6.722mol B ₓ (10.811g / mol) = <em>72.67g of B</em>

4 0
2 years ago
Fill in the blanks with the word that best completes each statement. Scientists develop knowledge by making ------------about th
kotegsom [21]

Answer:

1. observations

2. hypothesis

3. experimentation

Explanation:

Observations are made, Hypothesies are formed from observations, and experimnets help alter and comfirm hypothesis.

3 0
2 years ago
In an ionic bond:
inna [77]
Correct answer is 
<span>D. One atom accepts electrons from another.</span>
8 0
2 years ago
Read 2 more answers
For a school event 1/6 of the athletic field is reversed for the fifth -grade classes the reserved part of the field is divided
SVETLANKA909090 [29]

Answer:

\frac{1}{24}

Explanation:

Given:

For a school event, 1/6 of the athletic field is reserved for the fifth -grade classes and the reserved part of the field is divided equally among the 4 fifth grade classes in the school.

To find: fraction of the whole athletic field reserved for each fifth class

Solution:

Fraction of the whole athletic field reserved for four fifth classes = \frac{1}{6}

So, fraction of the whole athletic field reserved for each fifth class = \frac{1}{4}(\frac{1}{6})=\frac{1}{24}

3 0
2 years ago
At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?
Gnom [1K]
The temperature that  would  the volume of a gas  be 0.550l  if  it  had a volume of 0.432 L  at  -20.0  c is calculated  using the Charles law formula

that is   v1/T1=V2/T2
V1=0.550 l
t1=?
T2= -20 c +273 = 253 K
v2= 0.432 l

by  making T1  the subject of the formula  T1= V1T2/V2


T1=  (0.55lL x253)/  0.432 l = 322.11 K  or  322.11-273 = 49.11 C
8 0
2 years ago
Read 2 more answers
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