Which describes what a velocity/time graph would look like with no acceleration?
2 answers:
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Answer:
The correct answer is option C.
Explanation:
1.0 g sample of a cashew :
Heat released on combustion of 1.0 gram of cashew = -Q
We have mass of water = m = 1000 g
Specific heat of water = c = 4.184 J/g°C
ΔT = 30°C - 25°C = 5°C
Heat absorbed by the water : Q
Heat released on combustion of 1.0 gram of cashew is -20,920 J.
3.0 g sample of a marshmallows :
Heat released on combustion of 3.0 g sample of a marshmallows = -Q'
We have mass of water = m = 2000 g
Specific heat of water = c = 4.184 J/g°C
ΔT = 30°C - 25°C = 5°C
Heat absorbed by the water : Q'
Heat released on 3.0 g sample of a marshmallows= -Q' = -41,840 J
Heat released on 1.0 g sample of a marshmallows : q
Heat released on combustion of 1.0 gram of marshmallows -13,946.67 J.
-20,920 J. > -13,946.67 J
The combustion of 1.0 g of cashew releases more energy than the combustion of 1.0 g of marshmallow.
Answer:
There are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C
Explanation:
To decrease the temperature of the solution there are necessaries:
4,184J/g°C×(5,0°C-25,0°C)×(100,0g+X) = -Y
8368J + 83,68J/gX = Y <em>(1)</em>
Where x are grams of NH₄NO₃ you need to add and Y is the energy that you need to decrease the heat.
Also, the energy Y will be:
Y = 25700J/mol×X
Y = 321J/g X <em>(2)</em>
Replacing (2) in (1)
8368J + 83,68J/g X = 321J/g X
8363J = 237,32J/gX
<em>X = 35,2g</em>
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Thus, there are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C
I hope it helps!