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And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
If you do not mind me asking, what did Seth write? Us helpers cannot answer it if we do not have the full question. I apologize if this seems rude.
Answer:
A. There are not 15 successes and 15 failures. A confidence interval can be computed by adding 2 successes and 2 failures.
Answer:
<h2>One</h2>
Step-by-step explanation:
Given the value 78247 a s a stable number because at least one of its digits has the same value as its position in the number. The 4th number in the value is 4, this makes the number a stable number.
The following are the 3-digits stable numbers that appears in 78247
The first number is 824. This digits are stable numbers because 2 as a number is situated in the same place as the number (2nd position).
Hence, there are only 1 stable 3-digit numbers in the value 78247 since only a value exists as 2 in the value and there is no 1 and 3 in the value.
solution:
Consider the curve: r(t) = t²i +(int)j + 1/t k
X= t² , y = int ,z = 1/t
Using, x = t², z = 1/t
X = (1/z)²
Xz²= 1
Using y = int, z= 1/t
Y = in│1/z│
Using x = t², y = int
Y = int
= in(√x)
Hence , the required surface are,
Xz² = 1
Y = in│1/z│
Y= in(√x)
