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2 years ago

14

The first quartile of a data set is 18, the median is 25, the third quartile is 28, and an outlier is 45. Which of these data va

lues would be represented by a point in a modified box plot? A. 45 B. 28 C. 18 D. 25

2 answers:

Dmitriy789 [7]2 years ago

6 0

What is the answer can you help me

KengaRu [80]2 years ago

4 0

45 is the answer on apex learning.

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23. A 340 million square mile forest is how many hectares?

Firlakuza [10]

Answer:

88059595400 hectares

Step-by-step explanation:

Convert 340 million square miles into hectares.

1 square mile = 258.99881 hectares

340,000,000 square miles = 88059595400 hectares

The forest is 88059595400 hectares.

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2 years ago

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A bus traveling from Philadelphia to Boston travels at an average speed of 55 miles per hour. The bus stops for 1 hour halfway b

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55t+1=310
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2 years ago

Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9. Write the division problem

Sveta_85 [38]

Answer:

The required division problem he must solve is:

$\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}$

Step-by-step explanation:

Consider the provided information.

Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9.

As we know that the quotient of the number is a negative number.

Therefore, the sign of both numbers must be different,

Thus we can concluded he must select $\frac{2}{3}$ as one of the card, so that product is a negative number.

Let the selected card be x.

$\frac{2}{3} \div x =\frac{-16}{9}\\\\x=\frac{2}{3}\div\frac{-16}{9}\\\\x=\frac{2}{3}\times\frac{-9}{16}\\\\x=\frac{-3}{8}$

Hence, the two cards should be $\frac{2}{3}$ and $\frac{-3}{8}$

The required division problem he must solve is:

$\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}$

3 0

2 years ago

A car tire with a radius of 16inches is turning at a rate of 120 revolutions per minute. Find the exact linear speed of the tire

anygoal [31]

Answer:

The speed of the tyre of the car is 1002.24 feet per minute .

Step-by-step explanation:

Given as :

The radius of the car wheel = r = 16 inches

Since 12 inches = 1 feet

So, 16 inches = $\frac{1}{12}$ ×16 = 1.33 feet

The number of revolution of the wheel = 120 revolution per minute

Let The speed of the wheel = s feet per minute

The circumference of wheel = 2 × $\pi$ × radius

where $\pi$ = 3.14

or, circumference = 2 × 3.14 × 1.33

Or, Circumference = 8.352 feet

Now , Speed = circumference of wheel × number of revolution

or, Speed = 8.352 feet × 120 revolution per minute

∴ Speed = 1002.24 feet per minute

Hence The speed of the tyre of the car is 1002.24 feet per minute . Answer

4 0

3 years ago

A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s

denpristay [2]

Answer:

For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=40-1=39$

For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

3 0

2 years ago