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Vedmedyk [2.9K]
2 years ago
4

The population 3, 4, 9, 14, and 20 has a mean of 10 and a standard deviation of 6.356. The z-scores for each of the five data va

lues are z3 ≈ −1.101, z4 ≈ −0.944, z9 ≈ −0.157, z14 ≈ 0.629, and z20 ≈ 1.573. Find the mean and the standard deviation of these z-scores.
Mathematics
1 answer:
kow [346]2 years ago
7 0

Answer:

First, we find the square of the difference of the z values provided and sum them up giving us a value of 4.997956. We, therefore, calculate the sum of the sample mean given the number of samples to be 5 which gives us zero(0).

To calculate the standard deviation we use the formula that takes the square root of the inverse of the number of samples (n)*(the summation of the square of the difference between the sample and the mean which gives us 1.

*Step-by-step explaination

Given z3= -1.101, (z3 minus mean of z3)^2= 1.212201

Given z4= -0.944, (z4 minus mean of z4)^2=0.891136

Given z9= -0.157, (z9 minus mean of z9)^2= 0.024649

Given z14= 0.629, (z14 minus mean of z14)^2= 0.395641

Given z20= 1.573, (z20 minus mean of z20)^2= 2.474329

Therefore the summation of all Z values = Zero(0)

Also, the summation of (z values minus the mean of z values)^2= 4.997956

Therefore where n =5,

The sample mean of z values is given by the summation of z values divided by n = Zero (0)

To calculate standard deviation we use the formula that takes the square root of the inverse of the number of samples (n)*(the summation of the square of the difference between the sample and the mean which gives us 1.

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ANSWER ALL 5 PARTS.
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A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

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