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MatroZZZ [7]
2 years ago
6

130I decays by emission of beta particles to form stable 130Xe. A 3.00 g iodine sample containing some I-130 was recorded as hav

ing 9487 disintegrations per min. k = 0.00094 min -
1. How many radioactive I-130 atoms are present in the sample?
Chemistry
2 answers:
swat322 years ago
6 0

Answer:

idk

Explanation:

idk

Klio2033 [76]2 years ago
3 0

Answer:

a 3.oog

Explanation:

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A 0.15 m solution of chloroacetic acid has a ph of 1.86. What is the value of ka for this acid?
dem82 [27]

Answer: 1.67\times 10^{-3}

Explanation:

ClCH_2COOH\rightarrow ClCH_2COO^-+H^+

   cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Given:  c = 0.15 M

pH = 1.86

K_a = ?

Putting in the values we get:

Also pH=-log[H^+]

1.86=-log[H^+]

[H^+]=0.01

[H^+]=c\times \alpha

0.01=0.15\times \alpha

\alpha=0.06

As [H^+]=[ClCH_2COO^-]=0.01

K_a=\frac{(0.01)^2}{(0.15-0.15\times 0.06)}

K_a=1.67\times 10^{-3]

Thus the vale of K_a for the acid is 1.67\times 10^{-3}

4 0
2 years ago
Green light has a frequency of 6.01*10^14 Hz. What is the wavelength?
NemiM [27]
<span>λν = c

c= speed of light= 3.0x10^8 m/s
</span>λ=wavelength
v= frequency

Plug and Chug. 
8 0
2 years ago
The student decided to do another experiment with his leftover copper(II) sulfate (CuSO4) solution. He divided the solution up i
lakkis [162]

Answer:

CuSO4 + Fe -> FeSO4 + Cu

Explanation:

This reaction is a classic example of a redox reaction. I won't go in too deep, but the basic thing is that electrons from the Fe atom go to the Cu2+ ion. Therefore, Fe becomes an ion, and Cu - an electroneutral atom:

Fe + Cu2+ -> Fe2+ + Cu.

Silver is not a very reactive metal and it does not give up its electrons to Cu.

6 0
2 years ago
If 200mL of 0.60 M MgCl2 (aq) is added to 400mL of distilled water, what is the concentration of Mg2+(aq) in the resulting solut
lara [203]

Answer:

A.0.20M

Explanation:

c 1 V 1 = c 2 V 2

Initial Volume, V1 = 200 mL

Final Volume, V2 = 200 + 400 = 600 mL

Initial Concentration, c1 = 0.60 M

Final Concentration, c2= ?

Solving for c2;

c2 = c1v1 / v2

c2 = 0.60 * 200 / 600

c2 = 0.20M

3 0
1 year ago
Dead space is the portion of the respiratory system that: Select one: A.. must be filled with air before gas exchange can take p
ololo11 [35]

Answer: Option B

Explanation:

Dead space is the volume of sir in the body which is inhaled but it does not takes part in the gaseous exchange this is because it does not contains alveoli.

Not all the air that is inhaled inside the body is used in the process of respiration.

The dead space in the lungs is the region which helps in conducting airways, the air is not perfused to the alveoli.

5 0
2 years ago
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