Answer:
0.467 kilograms of protein or carbohydrates
Explanation:
First, there is a need to understand that <em>1 kJ = 0.239 kCal</em>
Hence, 17 kJ = 17 x 0.239 = 4.063 kCal
The race requires 650.0 kCal/hr and has to last for 175 minutes.
175 minutes = 175/60 = 2.917 hrs
The total kCal requires for the race = 650 x 2.917 = 1,895.833 kCal
1 g of protein or carbohydrate food produces 17.0 kJ or 4.063 kCal of energy. Hence, the total g of protein or carbohydrate that will produce 1,895.833 kCal of energy would be;
1,895.833/4.063 = 466.609 g
<em>1 g = 0.001 kg</em>
466.609 g = 466.609 x 0.001 = 0.467 kg
<em>Hence, </em><em>0.467 </em><em>kilograms of proteins or carbohydrates must be consumed.</em>
Answer:
78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene
Explanation:

Moles of propene = 
According to reaction, 1 mole of propene gives 1 mole of propane.
Then 0.6538 moles of bromo-propane will give:

78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene.
The oxidizing agent is the one that is reduced in the reaction. In this reaction, the charge of Cu falls from +2 to zero charge (neutral atom in the right side). Hence, CuO is the oxidizing agent. The reducing agent, the one being oxidized is carbon from zero charge to +4. The answer is CuO.
<u>Answer:</u> The average atomic mass of the element is 6.95 amu
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
We are given:
Mass of isotope 1 = 7.02 amu
Percentage abundance of isotope 1 = 92.6 %
Fractional abundance of isotope 1 = 0.926
Mass of isotope 2 = 6.02 amu
Percentage abundance of isotope 2 = 7.42 %
Fractional abundance of isotope 2 = 0.0742
Putting values in equation 1, we get:
![\text{Average atomic mass of element}=[(7.02\times 0.926)+(6.02\times 0.0742)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20element%7D%3D%5B%287.02%5Ctimes%200.926%29%2B%286.02%5Ctimes%200.0742%29%5D)

Hence, the average atomic mass of the element is 6.95 amu
Answer:
D.
The concentration of reactants and the concentration of products are constant.
Explanation:
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