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VikaD [51]
2 years ago
11

Identify the most and the least acidic compound in each of the following sets.

Chemistry
1 answer:
il63 [147K]2 years ago
3 0

Answer:

See explanation

Explanation:

Our answer options for this question are:

a. 2-chlorobutanoic acid:_______ 2-chlorobutanoic acid:_______ 3-chlorobutanoic acid:______.

b. 2,4-dinitrobenzoic acid:______ p-nitrobenzoic acid:______ p-bromobenzoic acid:_______.

c. p-cyanobenzoic acid:________ benzoic acid:_______ p-aminobenzoic acid:______

We have to check each set of molecules

<u>a. 2-chlorobutanoic acid,</u> <u>3-chlorobutanoic acid</u>

<u />

In this case, the difference between these molecules is the position of "Cl". If the chlorine atom is closer to the acid group, we will have a higher inductive effect. So, the bond O-H would be weaker and we will have more acidity. So, the molecule with more acidity is <u>2-chlorobutanoic acid</u> and the less acidic would be <u>3-chlorobutanoic acid.</u>

<u />

<u>b. 2,4-dinitrobenzoic acid,</u> <u>p-nitrobenzoic acid,</u> <u>p-bromobenzoic acid</u>

<u />

In this case, we have several structural differences. In all the structure, we have deactivating groups (Br and NO_2). If we have a deactivating group the acidity will increase. In the case of "Br", we have a weak deactivating, so, this will be the less acidic one (<u>p-bromobenzoic acid)</u>

in <u>2,4-dinitrobenzoic acid</u> we have two deactivating groups, therefore, this would be the most acid compound.

<u>c. p-cyanobenzoic acid</u>, <u>benzoic acid</u>, <u>p-aminobenzoic acid</u>

On these molecules, we have several structural differences. In <u>p-cyanobenzoic acid</u> we have a deactivating group, therefore in this molecule we will have more acidity. In the <u>p-aminobenzoic acid,</u> we have an activating group, so, this would be the less acidic compound.

<u />

See figure 1

I hope it helps!

<u />

<u />

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If angle ABE = 2n + 7 and angle EBF=4n-13,<br>find angle ABE.​
andreev551 [17]

Answer:

The measure of angle ABE is 27°.

Explanation:

Consider the below figure attached with this question.

Given information: ∠ABE=2n+7 and ∠EBF=4n-13.

From the below figure it is clear that ∠ABE and ∠EBF are congruent.

m\angle ABE=m\angle EBF

2n+7=4n-13

Isolate variable terms on one side.

7+13=4n-2n

20=2n

Divide both sides by 2.

10=n

The value of n is 10.

We need to find the measure of ∠ABE.

\angle ABE=2(10)+7=20+7=27

Therefore, the measure of angle ABE is 27°.

4 0
2 years ago
For a particular reaction, ΔH∘=67.7 kJ/molΔH∘=67.7 kJ/mol and Δ????∘=126.9 J/(mol⋅K).ΔS∘=126.9 J/(mol⋅K). Assuming these values
Pavlova-9 [17]

Answer:

T=533.49\, K

For temperatures higher than 533.49 K we will see a spontaneous reaction, and for temperatures lower than that the reaction will not be spontaneous.

Explanation:

When are chemical reactions spontaneous? To find out we need to look at the reaction's change in Gibbs Free energy:

\Delta G=\Delta H-T\Delta S

When this is greater than zero, the reaction isn't spontaneous, when it is less than zero, we have a spontaneous reaction. The reaction must then change from spontaneous to non spontaneous when \Delta G=0. If we insert that into our equation we get:

0=\Delta H-T\Delta S\\\\T=\frac{\Delta H}{\Delta S}

That is the temperature at which the reaction's spontaneity will change, plugging in our values we find:

T=533.49\, K

At that temperature we have  \Delta G=0.

Now, at a temperature greater than this one, the entropy term in our equation for the Gibbs' free energy of reaction will take over, and make  \Delta G, thus the reaction will be spontaneous.

On the other hand, if we lower the temperature, we will have a smaller entropy term, and we will have:  \Delta G>0. That is, the reaction will not be spontaneous. Therefore for temperatures higher than 533.49 K we will see a spontaneous reaction, and for temperatures lower than that the reaction will not be spontaneous.

8 0
2 years ago
A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
Sedbober [7]

Answer:

81°C.

Explanation:

To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat released from water (Q = - 1200 J).

m is the mass of the water (m = 20.0 g).

c is the specific heat capacity of water (c of water = 4.186 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = final T - 95.0°C).

∵ Q = m.c.ΔT

∴ (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).

(- 1200 J) = 83.72 final T - 7953.

∴ final T = (- 1200 J + 7953)/83.72 = 80.67°C ≅ 81.0°C.

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7 0
2 years ago
What is the number of moles in 15.0 g AsH3?
Grace [21]

Answer:

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Explanation:

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mass of AsH₃ = 15.0 g.

molar mass of AsH₃ = 77.95 g/mol.

∴ The number of moles in 15.0 g AsH₃ = mass / molar mass = (15.0 g) / (77.95 g/mol) = 0.192 mol.

7 0
1 year ago
Which of the following statements best describes the Aufbau principle?
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The answer is the choice A
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