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natima [27]
2 years ago
4

A gas originally at 27 °C and 1.00 atm pressure in a 3.3 L flask is cooled at constant pressure until the temperature is 11 °C.

The new volume of the gas is ________ L.
Chemistry
1 answer:
morpeh [17]2 years ago
3 0

Answer:

THE NEW VOLUME OF THE GAS IS 3.124 L

Explanation:

Initial Temperature = 27°C = 27 + 273 K = 300 K

Pressure = constant

Initial Volume = 3.3 L

Final Temperature = 11 °C = 11+ 273 K = 284 K

Final volume = unknown

Using Charles' law, at constant pressure, the volume of a given gas is directly proportional to the temperature.

Mathematically,

V1 / T1 = V2 / T2

Re-arranging the formula by making V2 the subject of the formula

V2 = V1 T2 / T1

V2 = 3.3 * 284 / 300

V2 = 3.124 L

The new volume of the gas is therefore 3.124 L at 11°C

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A column is filled with four different liquids of different densities. A red liquid, a blue liquid, a green liquid, and a purple
Svet_ta [14]

<em>Answer:</em>

The order of liquid from top to bottom is as follow

  •        Purple, green, red, blue

<em>Explanation:</em>

Chart of densities:

  •   Red = 1.2 g/cm∧3
  •   Blue = 1.6 g/cm∧3
  •   green = 0.8 g/cm∧3
  •   Purple = 0.1 g/cm∧3

<em>Density:   </em>

Density is the ratio of mass and volume as follow

                             d = m/v

<em>Summary:</em>

  • Greater the density, it will be at bottom and vice versa.
  • Blue liquid has greater density so it will be at bottom
  • Purple liquid has low density, so it will be at top.
5 0
2 years ago
Read 2 more answers
Consider four sealed, rigid containers with the following volumes: 50 mL, 100 mL, 250 mL, and 500 mL. If each of these contains
dsp73
First, we assume that helium behaves as an ideal gas such that the ideal gas law is applicable.
                                     PV = nRT
where P is pressure, V is volume, n is number of moles, R is universal gas constant, and T is temperature. From the equation, if n, R, and T are constant, there is an inverse relationship between P and V. From the given choices, the container with the greatest pressure would be the 50 mL. 
5 0
2 years ago
A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°c. what is the magnitude of k at 75.0°c if ea =
IgorC [24]
According to this formula:
K= A*(e^(-Ea/RT) when we have K =1.35X10^2 & T= 25+273= 298K &R=0.0821
Ea= 85.6 KJ/mol So by subsitution we can get A:
1.35x10^2 = A*(e^(-85.6/0.0821*298))
1.35x10^2 = A * 0.03
A= 4333
by substitution with the new value of T(75+273) = 348K & A to get the new K
∴K= 4333*(e^(-85.6/0.0821*348)
  = 2.16 x10^2
8 0
2 years ago
For no2−, write an equation that shows how the anion acts as a base. express your answer as a chemical equation. identify all of
katrin [286]
Hello!

Bases are defined by Arrhenius as substances which release OH⁻ ions when dissolved in water. NO₂⁻ complies with this definition by the chemical reaction that is shown below:

 NO₂⁻(aq) + H₂O (l) HNO₂ (aq) + OH⁻(aq)

Have a nice day!
5 0
2 years ago
Read 2 more answers
Which of the following shows an accurate combustion reaction?
Jet001 [13]

Answer:

  • <em>Cu + O₂  → CuO₂</em>

Explanation:

A <em>combustion reaction</em> is the reaction with oxygen along with the release of energy in form of heat or light.

Organic compounds (like CH₄) undergo combustion forming water and CO₂.

The combustion reaction of CH₄ is:

  • CH₄ + 2O₂ → CO₂ + 2H₂O

Hence, the first equation from the choices is not showing the combustion reaction of CH₄.

Not only organic compounds can undergo combustion. Metals and no metals can undergo combustion, i.e. metals and no metals can react with oxygen releasing light or heat.

The reaction of copper and oxygen (second choice) is a combustion reaction:

  • <em>Cu + O₂ → CuO₂</em>

The formation of water (2H₂ + O₂ → 2H₂O) is other example of a combustion reaction where no organic compounds are involved.

On the other hand, the other two equations from the choice list are not reactions with oxygen, so they do not show combustion reactions.

5 0
2 years ago
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