Question

What is the approximate value of x? Round to the nearest tenth. A right triangle is shown. Side x is opposite to angle 50 degrees. The hypotenuse has a length of 6 centimeters. Side y is opposite to angle 40 degrees. 3.1 cm 3.9 cm 4.6 cm 5.4 cm

Answer 1

Answer:

4.6cm

Step-by-step explanation:

A diagram showing the analysis from the question has been attached to this response. Kindly download it and view.

From the diagram,

=> We have three angles given

(i) the right angle, 90°

(ii) the angle opposite to side x, 50°

(iii) the angle opposite to side y, 40°

=> We also have one side given,

(i) the hypotenuse, of length 6cm

We can therefore apply the sine rule as follows;

$\frac{sin 90^0}{6} = \frac{sin 50^0}{x} = \frac{sin 40^0}{y}$           ---------------(i)

Now to get the value of x, we'll equation the first and second terms of equation (i) as follows;

$\frac{sin 90^0}{6} = \frac{sin 50^0}{x}$               [cross multiply]

$xsin90^0 = 6 sin 50^0$

$x * 1 = 6 * 0.7660$

$x =4.596$ cm = 4.6cm  [to the nearest tenth]

Therefore, the value of x is 4.6cm to the nearest tenth

Answer 2

Answer:

4.6 cm

Step-by-step explanation:

just took on edge