Renee jogs 2.5 miles 4 days a week. She calculates that she jogs a total of 10 miles each week. Use the drop-down boxes to expla
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Answer:
No. James didn't have enough ticket takers to process the average number of patrons hat usually attend the events.
He need to hire 2 more ticket taker (i.e 20 ticket takers) in order to process the average number of patrons hat usually attend the events.
Step-by-step explanation:
Given:
Average amount of patron per event= 7000
Each ticket taker can process = 350
Number of ticket takers hired = 18
We need to find the whether he hire enough to process the average number of patrons that usually attend the events.
Solution:
We will find the Average amount of patron ticket takers can process.
Now we can say that
Average amount of patron ticket takers can process is equal to Each ticket taker can process multiplied by Number of ticket takers hired.
framing in equation form we get;
Average amount of patron ticket takers can process =
Hence With the required hires James cannot fully process the patrons usually attending the event.
To find how many ticket takers required we will divide average number of patrons with Each ticket taker can process.
framing in equation form we get;
ticket takers required =
hence In order t process the the average number of patrons that usually attend the events James will require 20 ticket takers.
You haven't provided the series, therefore, I can only help with the concept.
<u><em>For an infinite geometric series, we have two possibilities for the common ratio (r):</em></u>
for r > 1, the terms in the series will keep increasing infinitely and the only possible logic summation of the series would be infinity
for r < 1, the terms will decrease, therefore, we can formulate a rule to get the sum of the infinite series
<u><em>In an infinite series with r < 1, the summation can be found using the following rule:</em></u>
sum =
where:
a₁ is the first term in the series
r is the common ratio
<u>Example:</u>
For the series:
2 , 1, 0.5 , 0.25 , ....
we have:
a₁ = 2
r = 0.5
Therefre:
sum =
Hope this helps :)
<u><em>For an infinite geometric series, we have two possibilities for the common ratio (r):</em></u>
for r > 1, the terms in the series will keep increasing infinitely and the only possible logic summation of the series would be infinity
for r < 1, the terms will decrease, therefore, we can formulate a rule to get the sum of the infinite series
<u><em>In an infinite series with r < 1, the summation can be found using the following rule:</em></u>
sum =
where:
a₁ is the first term in the series
r is the common ratio
<u>Example:</u>
For the series:
2 , 1, 0.5 , 0.25 , ....
we have:
a₁ = 2
r = 0.5
Therefre:
sum =
Hope this helps :)