Question

The biomass B(t) of a fishery is the total mass of the members of the fish population at time t. It is the product of the number of individuals N(t) in the population and the average mass M(t) of a fish at time t. In the case of guppies, breeding occurs continually. Suppose that at time t = 5 weeks the population is 824 guppies and is growing at a rate of 50 guppies per week, while the average mass is 1.3 g and is increasing at a rate of 0.14 g/week. At what rate is the biomass increasing when t = 5? (Round your answer to one decimal place.) B'(5) = g/week

Answer 1

Answer:

The rate at which the biomass is increasing when t = 5 is 180.36 g/week

Step-by-step explanation:

Given that :

t = 5 weeks

Population N(t) = 824 guppies

Growth Rate $\dfrac{dN(t)}{dt}= 50 \ guppies /week$

average mass M(t) = 1.3 g

increase rate of biomass  $\dfrac{dM (t)}{t}$= 0.14 g/week

Therefore; the rate at which the biomass is increasing when t = 5 is:

$\dfrac{dB(t)}{dt}= M(t) * \dfrac{dN(t)}{dt}+ N(t)* \dfrac{dM (t)}{t}$

$\dfrac{dB(t)}{dt}=1.3 * 50+ 824* 0.14$

$\dfrac{dB(t)}{dt}=65+115.36$

$\mathbf{\dfrac{dB(t)}{dt}=180.36 \ g/week}$

The rate at which the biomass is increasing when t = 5 is 180.36 g/week