Ask question

Ask question

All categories

2 years ago

3

Lydia graphed ADEF at the coordinates D(- 2, - 1) * E * (- 2, 2) , and F(0, 0) . She thinks triangle DEF is a right triangle. Is

Lydia's assertion correct?

1 answer:

Ipatiy [6.2K]2 years ago

4 0

Yes the assertion is correct

You might be interested in

The scatterplot shows the sales, in dollars, of snow cones in relation to the outside temperature, in degrees Celsius. According

maksim [4K]

B) it is 450 dollars

7 0

2 years ago

Read 2 more answers

a garden plot is to contain 240 sq. ft. if its length is to be 3 times its width,what should its dimensions be?

Nastasia [14]

W^2=80
W SQRT80
W=8.94 ANS.FOR THE WIDTH
L=3*8.94=26.83 ANS.FOR THE LENGTH
PROOF:
240=8.94*26.83
240=240

3 0

2 years ago

We went to the market to buy some fruit. We decided to buy some apples, strawberries, and oranges. If we buy 2 apples, 3 boxes o

Ksivusya [100]

Step-by-step explanation:

Let the amount of apples bought be x

Amount of strawberries bought be y and;

amount of oranges bought be z

If we buy 2 apples, 3 boxes of strawberry, and 4 oranges, the fruit would cost $15.30, then this will be expressed as;

2x+3y+4z = 15.30 ........... 1

If we buy 1 box of strawberry, 4 apples, and 2 oranges, the fruit would cost $10.90, this will be expressed as:

4x+y+2z = 10.90 ......... 2

If we buy 1 orange, 5 apples and 2 boxes of strawberry, the fruit would cost $13.70, this is expressed as:

5x+2y+x = 13.70 .......... 3

Solving the three equations simultaneously:

2x+3y+4z = 15.30 ........... 1

4x+y+2z = 10.90 ......... 2

5x+2y+z = 13.70 .......... 3

Reduce the number of equations

multiply equation 1 by 2 and subtract from equation 2

equation 1 * 2 will give:

4x+6y+8z = 30.6 ........... 4

eqn (4)-eqn(2)

6y-y + 8z-2z = 30.6-10.90

5y+6z = 19.7 ......... 5

Also multiply equation 2 by 5 and eqn 5 by 4 and subtract from each other.

eqn(2)* 5 will give:

20x+5y+10z = 54.5 .......... *

eqn(3) * 4 will give

20x+8y+4z = 54.8.......**

Subtsrct ** from *

8y-3y+(4z-10z)= 54.8-54.5

5y-6z = 0.3 .................. 6

Equate 5 and 6 and solve:

5y+6z = 19.7 ......... 5

5y-6z = 0.3 .................. 6

subtract:

6z+6z = 19.7+0.3

12z = 20

z = 20/12

z = 1.67

Substitute z = 1.67 into eqn 6

5y-6(1.67) = 0.3

5y - 10 = 0.3

5y = 10.3

y = 10.3/5

y = 2.06

Substitute z = 1.67 and y = 2.06 into equation 1

From 1:

2x+3y+4z = 15.30

2x+3(2.06)+4(1.67) = 15.30

2x+6.18+6.68 = 15.30

2x+12.86 = 15.30

2x = 15.30-12.86

2x = 2.44

x = 2.44/2

x = 1.22

<em>Therefore 1 apple costs $1.22, 1 strawberry costs $2.06 and 1 orange costs $1.67</em>

3 0

2 years ago

In circle A shown, BC || DE , mBC=58° and mDE=142°. Determine the measure of ZCFE . Show how you arrived at your answer.

AysviL [449]

Answer:

< CFE = 40°

Step-by-step explanation:

To better understand the solution, see attachment for the diagram.

Given:

BC parallel to DE

Measure of Arc BD = 58°

Measure of Arc DE = 142°

First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.

The line ST divides the arc BD and arc DE into half.

That is:

Arc SC = 1/2(arc BC) =1/2(58)

Arc SC = 29°

Arc TE = 1/2(arc DE) =1/2(142)

Arc TE = 71°

Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle

29° + Arc CE + 71° = 180°

Arc CE + 100° = 180°

Arc CE = 180-100

Arc CE = 80°

Inscribed angle = 1/2(intercepted angle)

<CFE = 1/2(Arc CE )

<CFE = 1/2(80)

< CFE = 40°

5 0

2 years ago

The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. H

Lina20 [59]

The arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

<em><u>Explanation</u></em>

The given formula is: $s=V_{0}t-16t^2$

If the initial velocity is 96 ft/s , that means $V_{0}=96$

For finding the time the arrow takes to reach a height of 48 ft, we will plug $s= 48$ into the above formula. So......

$48=96t-16t^2\\ \\ 16t^2-96t+48=0\\ \\ 16(t^2-6t+3)=0\\ \\ t^2-6t+3=0\\ \\ t^2-6t =-3\\ \\ t^2-6t+9=-3+9\\ \\ (t-3)^2 = 6\\ \\ t-3= \pm \sqrt{6} \\ \\ t=3\pm \sqrt{6}\\ \\ t = 5.45 , 0.55$

So, the arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

7 0

2 years ago

Read 2 more answers