Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.
Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.
Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
Answer:
Step-by-step explanation:
The expression is
x^2 - 4
This is a quadratic expression.
To find the solution, we will equate the the expression to zero. It becomes
x^2 - 4 = 0
Add 4 to the left hand side of the equation and the right hand side of the equation. It becomes.
x^2 - 4 + 4 = 0 + 4
x^2 = 4
Take square root of the right hand side of the equation and left hand side of the equation. It becomes
√x^2 = √4
x = ± 2
x = 2 or x = - 2
Answer: C
Y=90+6x/x
90 new tools + 6 dollars (x) over x dollars
The answer in this question is 97.
0.20 SD = 1.96 SD / sqrt(n)
n = (1.96 / .200)^2
n = 96.04
Which is rounded Up to 97
The number of observations within the data set must be greater than or equal to the quantity of 97.
