Answer:
<h2>p(B) =
8310</h2>
Step-by-step explanation:
We will use the addition rule of probability of two events to solve the question. According to the rule given two events A and B;
p(A∪B) = p(A)+p(B) - p(A∩B) where;
A∪B is the union of the two sets A and B
A∩B is the intersection between two sets A and B
Given parameters
P(A)=15
P(A∪B)=1225
P(A∩B)=7100
Required
Probability of event B i.e P(B)
Using the expression above to calculate p(B), we will have;
p(A∪B) = p(A)+p(B) - p(A∩B)
1225 = 15+p(B)-7100
p(B) = 1225-15+7100
p(B) = 8310
Hence the missing probability p(B) is 8310.
Answer:
The coefficients are
11,-4 and 0
Step-by-step explanation:
We are given two algebraic expressions. We are subtracting the second from the first.
First one is
Second expression is
The given expression
=
The coefficients are
11,-4 and 0
The given function is
f(x) = 4x - 3/2
where
f(x) = number of assignments completed
x = number of weeks required to complete the assignments
We want to find f⁻¹ (30) as an estimate of the number of weeks required to complete 30 assignments.
The procedure is as follows:
1. Set y = f(x)
y = 4x - 3/2
2. Exchange x and y
x = 4y - 3/2
3. Solve for y
4y = x + 3/2
y = (x +3/2)/4
4. Set y equal to f⁻¹ (x)
f⁻¹ (x) = (x + 3/2)/4
5. Find f⁻¹ (30)
f⁻¹ (30) = (30 + 3/2)/4 = 63/8 = 8 (approxmately)
Answer:
Pedro needs about 8 weeks to complete 30 assignments.
So by definition, area is equal to the length (x) times the width (y). The area of the square mat is = x × y, or xy
If the area of<span> the rectangular mat is twice that of the square mat, the area of the rectangular mat would have to be = 2 </span>× x × y<span>
This can be written as 2x </span>× y, making the length of the rectangular mat twice that of the square mat's length, and the width the same as the square mat's width.<span>
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