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rosijanka [135]

2 years ago

3

Brandon mows his lawn once every 4 days. Thomas mows his lawn once every 8 days. Celena mows her lawn once every 6 days. If they

are all mowing the lawn today, in how many days will they be mowing their lawns together again? A. 72 B. 24 C. 18 D. 12

1 answer:

Aneli [31]2 years ago

8 0

Answer: B

Step-by-step explanation:

4,8 and 6 all go into 24

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On any night, there is a 92% chance that an burglary attempt will trigger the alarm, and a 1% chance of a false alarm, namely th

Semmy [17]

Answer:

Step-by-step explanation:

Step1: P(Burglary) = .001

Step2: P(Alarm|Burglary Happens) = .92

Step3: Probability of alarm going (in total) = P(Alarm) when burglary happens + P(Alarm) when burglary does not happen.

Step4: Use Bayes theorem.

3 0

2 years ago

a linguist had a gross income of $53,350 last year if 17.9% of his income got withheld for federal income tax how much of the li

laila [671]

Answer:

The linguists paid $9,549.65 in federal taxes.

Step-by-step explanation:

7 0

2 years ago

Find the additive inverse of 6-3i.

puteri [66]

Hey there!

In order to find the additive inverse of any number, regardless if it is real or not, you can simply multiply the number by -1 or negate it.

This should look like this:
-(6-3i)
=-6+3i

Therefore, the additive inverse of 6-3i is -6+3i.

**Note: Keep in mind, when the additive inverse of a number is added to the number, the number equals 0:
(6-3i)+(-6+3i)=0

Hope this helps and have a marvelous day! :)

5 0

2 years ago

What is the pressure difference Δp=pinside−poutside? Use 1.28 kg/m3 for the density of air. Treat the air as an ideal fluid obey

Sidana [21]

This is an incomplete question, here is a complete question.

A hurricane wind blows across a 7.00 m × 12.0 m flat roof at a speed of 150 km/h.

What is the pressure difference Δp = p(inside)-p(outside)? Use 1.28 kg/m³ for the density of air. Treat the air as an ideal fluid obeying Bernoulli's equation.

Answer : The pressure difference will be, $1.11\times 10^3Pa$

Step-by-step explanation :

As we are given:

Speed = 150 km/h = 41.66 m/s

Density = $\rho=1.28kg/m^3$

Area = A = 7.00 m × 12.0 m

Formula used :

$\Delta P=\frac{1}{2}\times \rho \times v^2$

Now put all the given values in this formula, we get:

$\Delta P=\frac{1}{2}\times (1.28kg/m^3)\times (41.66m/s)^2$

$\Delta P=1.11\times 10^3Pa$

Thus, the pressure difference will be, $1.11\times 10^3Pa$

7 0

2 years ago

Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4

vekshin1

<u>Given:</u>

The given equation is $\log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)$

We need to determine the extraneous solution of the equation.

<u>Solving the equation:</u>

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule $\log _{c}(a)+\log _{c}(b)=\log _{c}(a b)$ , we get;

$\log _{4}(x(x-3))=\log _{4}(-7 x+21)$

Again applying the log rule, if $\log _{b}(f(x))=\log _{b}(g(x))$ then $f(x)=g(x)$

Thus, we have;

$x(x-3)=-7 x+21$

Simplifying the equation, we get;

$x^2-3x=-7 x+21$

$x^2+4x=21$

$x^2+4x-21=0$

Factoring the equation, we get;

$(x-3)(x+7)=0$

Thus, the solutions are $x=3, x=-7$

<u>Extraneous solutions:</u>

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

$\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)$

$\log _{4}(3)+\log _{4}(0)=\log _{4}(0)$

Since, we know that $\log _{a}(0)$ is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

$\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)$

Simplifying, we get;

Undefined = $\log _{4}(70)$

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

7 0

2 years ago

Read 2 more answers