Question

Fiona wrote the linear equation y = y equals StartFraction 2 over 5 EndFraction x minus 5.x – 5. When Henry wrote his equation, they discovered that his equation had all the same solutions as Fiona’s. Which equation could be Henry’s? x – x minus StartFraction 5 over 4 EndFraction y equals StartFraction 25 over 4 EndFraction.y = x – x minus StartFraction 5 over 2 EndFraction y equals StartFraction 25 over 4 EndFraction.y = x – x minus StartFraction 5 over 4 EndFraction y equals StartFraction 25 over 2 EndFraction.y = x – x minus StartFraction 5 over 2 EndFraction y equals StartFraction 25 over 2 EndFraction.y =

Answer 1

Answer:

D. $x-\frac{5}{2}y = \frac{25}{2}$

Step-by-step explanation:

Given

$y = \frac{2}{5}x - 5$

Required

Determine its equivalent

From the list of given options, the correct answer is

$x - \frac{5}{2}y = \frac{25}{2}$

This is shown as follows;

$y = \frac{2}{5}x - 5$

Multiply both sides by $\frac{5}{2}$

$\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)$

Open Bracket

$\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5$

$\frac{5}{2}y = x - \frac{25}{2}$

Subtract x from both sides

$\frac{5}{2}y - x = x -x - \frac{25}{2}$

$\frac{5}{2}y - x = - \frac{25}{2}$

Multiply both sides by -1

$-1 * \frac{5}{2}y - x * -1 = - \frac{25}{2} * -1$

$-\frac{5}{2}y + x = \frac{25}{2}$

Reorder

$x-\frac{5}{2}y = \frac{25}{2}$

Hence, the correct option is D

$x-\frac{5}{2}y = \frac{25}{2}$

Answer 2

Answer:

The 4th option

Step-by-step explanation: