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lisov135 [29]
1 year ago
7

Fiona wrote the linear equation y = y equals StartFraction 2 over 5 EndFraction x minus 5.x – 5. When Henry wrote his equation,

they discovered that his equation had all the same solutions as Fiona’s. Which equation could be Henry’s? x – x minus StartFraction 5 over 4 EndFraction y equals StartFraction 25 over 4 EndFraction.y = x – x minus StartFraction 5 over 2 EndFraction y equals StartFraction 25 over 4 EndFraction.y = x – x minus StartFraction 5 over 4 EndFraction y equals StartFraction 25 over 2 EndFraction.y = x – x minus StartFraction 5 over 2 EndFraction y equals StartFraction 25 over 2 EndFraction.y =
Mathematics
2 answers:
xeze [42]1 year ago
9 0

Answer:

D. x-\frac{5}{2}y =  \frac{25}{2}

Step-by-step explanation:

Given

y = \frac{2}{5}x - 5

Required

Determine its equivalent

<em>From the list of given options, the correct answer is</em>

x - \frac{5}{2}y = \frac{25}{2}

This is shown as follows;

y = \frac{2}{5}x - 5

Multiply both sides by \frac{5}{2}

\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)

Open Bracket

\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5

\frac{5}{2}y = x - \frac{25}{2}

Subtract x from both sides

\frac{5}{2}y - x = x -x - \frac{25}{2}

\frac{5}{2}y - x = - \frac{25}{2}

Multiply both sides by -1

-1 * \frac{5}{2}y - x * -1 = - \frac{25}{2} * -1

-\frac{5}{2}y + x =  \frac{25}{2}

Reorder

x-\frac{5}{2}y =  \frac{25}{2}

<em>Hence, the correct option is D</em>

x-\frac{5}{2}y =  \frac{25}{2}

Alina [70]1 year ago
8 0

Answer:

The 4th option

Step-by-step explanation:

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