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dybincka [34]
2 years ago
10

Given the following values of pKa, determine which is the weakest base of the answers listed. Acid pKa HClO2 1.95 HClO 7.54 HCOO

H 3.74 HF 3.17 HNO2 3.15
Chemistry
1 answer:
professor190 [17]2 years ago
4 0

Answer:

HClO 7.54

Explanation:

Hypochlorous acid (HClO) is a weakest acid because the pKa value of Hypochlorous acid is very high among the options given in the activity. pKa is a method which is used in order to identify the strength of an acid. The higher the value of pKa of a liquid, lower the strength of an acid while lower the value of pKa of chemical, higher the strength of an acid. In the options, HClO2  is a strong acid due to high lower pKa value.

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a 16.0g sample of iron was heated from 0 degrees Celsius o 35.0 degrees Celsius.the iron absorbed 246.4J of energy as heat. what
frosja888 [35]
Specific heat means the amount heat needed when unit mass of a substrate increase one degree of temperature. So the specific heat = the heat absorbed/(the mass of the substrate * change in temperature) = 264.4/(16*35)=0.472 J/(g*℃)
5 0
2 years ago
Read 2 more answers
How many moles of chromium metal equal 7.52 × 1022 atoms Cr?
grigory [225]

Answer:

0.125 mole

Explanation:

From Avogadro's hypothesis, we discovered that 1 mole of any substance contains 6.02x10^23 atoms.

The statement above suggests that 1 mole of chromium contains 6.02x10^23 atoms.

Now, if 1mole of of chromium contains 6.02x10^23 atoms,

Then Xmol of chromium contains 7.52x10^22 atoms i.e

Xmol of chromium = 7.52x10^22/6.02x10^23

Xmol of chromium = 0.125 mole

Therefore, 0.125 mole of chromium contains 7.52x10^22 atoms

8 0
2 years ago
Exactly 500 grams of ice are melted at a temperature of 32°f. (lice = 333 j/g.) calculate the change in entropy (in j/k). (give
denpristay [2]
Entropy Change is calculated  by (Energy transferred) / (Temperature in kelvin) 
deltaS = Q / T 

Q = (mass)(latent heat of fusion) 
Q = m(hfusion) 
Q = (500g)(333J/g) = 166,500J 

T(K) = 32 + 273.15 = 305.15K 
deltaS = 166,500J / 305.15K 
deltaS = 545.63 J/K
3 0
2 years ago
Consider the solutions, 0.04 m urea [(NH2)2C=O)], 0.04 m AgNO3 and 0.04 m CaCl2. Which has (i) the highest osmotic pressure, (ii
Lana71 [14]

Answer:

i) Highest osmotic pressure: CaCl2

ii) lower vapor pressure : CaCl2

iii) highest boiling point : CaCl2

Explanation:

The colligative properties depend upon the number of solute particles in a solution.

The following four are the colligative properties:

a) osmotic pressure : more the concentration of the solute, more the osmotic pressure

b) vapor pressure: more the concentration of the solute, lesser the vapor pressure.

c) elevation in boiling point: more the concentration of the solute, more the boiling point.

d) depression in freezing point: more the concentration of the solute, lesser the freezing point.

the number of particle produced by urea = 1

the number of particle produced by AgNO3 = 2

the number of particle produced by CaCl2 = 3

As concentrations are same, CaCl2 will have more number of solute particles and urea will have least

i) Highest osmotic pressure: CaCl2

ii) lower vapor pressure : CaCl2

iii) highest boiling point : CaCl2

5 0
2 years ago
Suppose there is a gaseous mixture of nitrogen and oxygen. If the total pressure of the mixture is 470 mmHg , and the partial pr
ch4aika [34]

Answer:

190 mmHg

Explanation:

According to Dalton's law, in a mixture of ideal gases, each gas behaves independently of the other. Also, the total pressure is equal to the sum of the individual partial pressures.

The total pressure of the mixture is 470 mmHg , and the partial pressure of nitrogen is 280 mmHg. Then,

P = pO₂ + pN₂

pO₂ = P - pN₂

pO₂ = 470 mmHg - 280 mmHg

pO₂ = 190 mmHg

5 0
2 years ago
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