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Ksenya-84 [330]
2 years ago
3

Create diagrams to represent the possible cases for common tangents between two circles. Your diagram can be created using multi

media sources or drawn by hand. They should not be copied and pasted from a website. Explain why your diagrams satisfy the given criteria. One Common Tangent (10 points) Diagram: Justification:

Mathematics
2 answers:
olchik [2.2K]2 years ago
3 0

Answer:

draw 2 lines and draw 2 circles in the lines with the edge touching the line

Step-by-step explanation:

hodyreva [135]2 years ago
3 0
Draw to 2 lines and 2 circles with the line touching the edge
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The weight of Jacob’s backpack is made up of the weight of the contents of the backpack as well as the weight of the backpack it
Dafna11 [192]
If the backpack (b) contains only textbooks (t) and notebooks (n), the total weight of the backpack is:

b+t+n

but notebooks are 4 pounds, so actually:

b+t+4

also, the backpack weights 2 pounds, so the total weight is:

2+t+4 =t+6
 now, "Seventy percent of <span> the total weight is textbooks. ", this means that


t=70%(t+6) - this equation can be used to determine the weight of the textbooks!
</span> 




7 0
2 years ago
Read 2 more answers
A ramp leading into a building makes a 15o angle with the ground. the end of the ramp is 10 feet from the base of the building.
Oksanka [162]
We are tasked to solved for the length of the ramp having an inclination of 15 degrees with the ground and 10 feet from the end of the ramp to the base of the building of the ground. Using trigonometric properties, we have a formula given an angle and the its opposite sides which is,
sin(Angle)=opposite/hypothenuse
hypothenuse would be the distance or the length of the ramp.
so we have,
sin(15)=10/hypothenuse
Cross-multiply, we have,
hypothenuse=10/sin(15)
using scientific calculator having a DEG mode,
hypothenuse=38.63703
Rounding of in nearest tenth we get,
hypothenuse=38.6 ft
Therefore, the ramp is 38.6 ft long
3 0
2 years ago
The foodservice department has been asked to prepare a special luncheon for the grandway hospital board of directors on tuesday.
AURORKA [14]
125/21 = 150/x
cross multiply
125x = 3150
x = 3150/125
x = 25.2 lbs....rounded up = 26 lbs <==
5 0
2 years ago
Determine which functions have two real number zeros by calculating the discriminant, b2 – 4ac. Check all that apply. Please ans
timama [110]
<span>The discriminant of a quadratic equation is the b^2-4ac portion that the square root is taken of. If the discriminant is negative, then the function has 2 imaginary roots, if the discriminant is equal to 0, then the function has only 1 real root, and finally, if the discriminant is greater than 0, the function has 2 real roots. So let's look at the equations and see which have a positive discriminant. f(x) = x^2 + 6x + 8 6^2 - 4*1*8 36 - 32 = 4 Positive, so f(x) has 2 real roots. g(x) = x^2 + 4x + 8 4^2 - 4*1*8 16 - 32 = -16 Negative, so g(x) does not have any real roots h(x) = x^2 – 12x + 32 -12^2 - 4*1*32 144 - 128 = 16 Positive, so h(x) has 2 real roots. k(x) = x^2 + 4x – 1 4^2 - 4*1*(-1) 16 - (-4) = 20 Positive, so k(x) has 2 real roots. p(x) = 5x^2 + 5x + 4 5^2 - 4*5*4 25 - 80 = -55 Negative, so p(x) does not have any real roots t(x) = x^2 – 2x – 15 -2^2 - 4*1*(-15) 4 - (-60) = 64 Positive, so t(x) has 2 real roots.</span>
4 0
2 years ago
Read 2 more answers
An orange is shot up into the air with a catapult. The function h given by h(t)=15+60t-16t^2 models the orange’s height, in feet
Studentka2010 [4]

Complete question is:An orange is shot up into the air with a catapult. The function h given by h(t) = 15 + 60t - 16t² models the orange’s height, in feet, t seconds after it was launched.

Select all the true statements about the situation.

Options:

1. The domain of function h only contains values greater than or equal to 0.

2. The orange is at the same height 1 second after launch and 2 seconds after launch.

3. After 3 seconds, the orange has hit the ground.

4. The orange is 15 feet above the ground when it is launched.

5. The value t = 10 does not belong to the domain of h.

Answer:

Option 1 - True

Option 2 - False

Option 3 - False

Option 4 - True

Option 5 - True

Step-by-step explanation:

Looking at the options,

-The domain is the x or t value and it is time. Now, time can only be positive or greater than or equal to zero i.e. t ≥ 0. Thus, option 1 is true.

- At t = 1 second;

h = 15 + 60(1) - 16(1)²

h = 15 + 60 - 16 = 59 ft

Also, at t = 2 seconds;

h = 15 + 60(2) - 16(2)²

h = 15 + 120 - 64 = 71 ft

So,value of h is not the same at t = 1 and t = 2. Thus, option 2 is not true.

- The orange will hit the ground when h(t) = 0.

However, at t = 3;

h(t) = 15 + 60(3) - 16(3)²

h(t) = 51 ft

h(t) is not equal to zero at t = 3, so option 3 is false

- when the orange is launched it is at time t = 0.

Thus,

h(0) = 15 + 60(0) - 16(0)²

h(0) = 15 ft

So option 4 is true.

- At t=10, h(t) = 15 + 60(10) - 16(10)²

h(10) = -985

This means the orange would be below ground level and thus doesn't belong to the domain of h, so option 5 is true.

6 0
2 years ago
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