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2 years ago

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A piece of buttered toast falls to the floor 17 times. The toast landed buttered side up 6 times. What is the probability that t

he toast lands buttered side down?

1 answer:

kirza4 [7]2 years ago

8 0

Step-by-step explanation:

Given that,

A piece of buttered toast falls to the floor 17 times. The toast landed buttered side up 6 times.

It means that the total number of outcomes are 17

We need to find the probability that the toast lands buttered side down. Favourable oucome is 17-6 = 11

So, probability is given by :

$P(E)=\dfrac{\text{favourable outcomes}}{\text{total no of outcomes}}$

$P(E)=\dfrac{11}{17}$

So, the probability that the toast lands buttered side down is 11/17.

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A machine called Feynman, produces output, that is 5 times its input followed by an increase of 2. Another machine called Maxwel

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1 year ago

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The perimeter of the base of a regular quadrilateral prism is 60 cm, the area of one of the lateral faces is 105 cm2.

yawa3891 [41]

For a better understanding of the solution, please follow the diagram in the attached file.

A regular quadrilateral is basically a square.

So, if the base of the prism has a perimeter of 60 cm, then the length of the side of the square will be $\frac{60}{4}=15 cm$ . It is shown of the diagram.

Now, from the diagram, it is clear that the lateral face area, which is given as 105 cm^2, is the product of the side of the square, which is known, and the unknown height, let us call it h. Thus, we will get the following equation:

$15\times h=105$

$\therefore h=\frac{105}{15}=7 cm$

This is depicted on the diagram.

Now, all our required parameters are in place. Thus, let us find what has been asked.

<u>SURFACE AREA</u>

Surface Area (SA) will be the sum of the areas of the two bases (squares) and the areas of the four lateral faces.

Since the side of one square base is 15 cm, therefore, the area of one square base will be $15^2$ .

Likewise, the area of one lateral surface is actually the area of a rectangle with length 15 cm and height 7 cm. Thus, it's area will be given as: $15\times 7$ .

Thus, our equation will be:

$SA=2\times 15^2+4\times 15\times 7=870 cm^2$

Therefore, Surface Area=870 cm^2

<u>VOLUME OF THE PRISM</u>

The volume of the prism will simply be the area of the base times the height of the prism.

Thus, the volume is:

$Volume=15^2\times 7=1575 cm^3$

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2 years ago

(iii) Find the smallest whole number h such that<br>4704/h<br>is a cube number.<br>

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Answer:

$h=588$

Step-by-step explanation:

Given the fraction $\dfrac{4,704}{h}$

Consider its numerator and factor it:

$4,704=2^5\cdot 3\cdot 7^2$

You cann not take the cube root from $3, 7^2, 2^5,$ you can only take the cube root from $2^3$ , then the smallest whole number $h$ such that $\dfrac{4,704}{h}$ is a cube number is

$h=2^2\cdot 3\cdot 7^2=4\cdot 3\cdot 49=588$

When $h=588,$

$\dfrac{4,704}{588}=8=2^3$

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1 year ago

Jerry makes $40,000 a year working at a nearby factory. He gets two weeks paid vacation per year, plus five other paid holidays.

JulijaS [17]

Answer:

Vacation pays are not included in salaries. Therefore, Jerry's calculation is wrong.

Step-by-step explanation:

Given is :

Jerry makes $40,000 a year working at a nearby factory.

He gets two weeks paid vacation per year, plus five other paid holidays.

So total paid holidays become = $14+5=19$ days

Subtracting 19 from 365 days and assuming that Jerry works for 365 days a year.

We get = $365-19=346$ days

So, his per day salary will be = $\frac{40000}{346}= 115.60$

Vacation pays are not included in salaries. Therefore, Jerry's calculation is wrong.

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2 years ago

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in a certain class, 22 pupils take one or more of chemistry, economic, government. 12 take economic (E), 8 take government (G) a

mash [69]

Answer:

ai) n(E⋂C) = ∅ = null

n(E⋂G) = 4

aii) see attachment

bi) n(C⋂G) = x = 1

bii) n(G) only = 3

Step-by-step explanation:

Let chemistry = C

Economic = E

Government = G

n(E) = 12

n(G) = 8

n(C) = 7

ai) number of pupils for economics and chemistry = 0

number of pupils for economics and government = 4

The set notation for both:

n(E⋂C) = ∅ = null

n(E⋂G) = 4

aii) find attached the Venn diagram

bi) n(C⋂G) = ?

Let number of n(C⋂G) = x

From the Venn diagram

n(C) only = 12-4 = 8

n(G) only = 8-(4+x) = 4-x

n(E) only = 7-x

n(E⋂C⋂G) = 0

n(E⋂C) = 0

n(E⋂G) = 4

Total: 8+ 4-x + 7-x + x + 0+0+4 = 22

23 -x = 22

23-22 = x

x = 1

n(C⋂G) = x = 1

Number of pupils that take both chemistry and government = 1

(bii) government only = n(G) only = 4-x

n(G) only = 4-1 = 3

Number of students that take government only = 3

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1 year ago