Answer:
Compute the cost of driving for two different job options.
Driving costs 0.50 dollars per mile. Driving occurs 250 days per year.
Job 1
Miles each way 5
What is the cost of driving?
Job 2
Miles each way 50
What is the cost of driving?
Answer:
We need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.
Step-by-step explanation:
Let's first list the percentage compositions of each fertilizer type:
<u>Vigoro Ultra Turf:</u>
Nitrogen (N) = 29 kg
Phosphoric Acid (P2O5) = 3 kg
Potash (K2O) = 4 kg
<u>Parkers Premium</u>
Nitrogen (N) = 18 kg
Phosphoric Acid (P2O5) = 25 kg
Potash (K2O) = 6 kg
We can set up simultaneous equations to find out the amount of 100 kg bags of each fertilizer needed:
x = Vigoro Ultra turf (one bag)
y = Parkers Premium (one bag)
29x + 18y = 217 -Equation 1
3x + 25y = 115 -Equation 2
4x + 6y = 44 -Equation 3
Solving for x and y, we get:
x = 5
y = 4
This means we need 5 bags of Vigoro Ultra Turf and 4 bags of Parkers Premium fertilizer.
Answer:
2^27
Step-by-step explanation:
Given the following expression:
[(2^10)^3 x (2^-10)] ÷ 2^-7
This can be easily simplified. Let us simplify the numerator first. To do that, we have
(2^10)^3 making use of the power rule of indices that says:
(A^a)^b = A^ab where a and b are powers, we have:
2^(10x3) = 2^30
Therefore the numerator becomes:
2^30 x 2^-10. Also making use of the multiplication rule that says:
A^a x A^b = A^(a + b), we have
2^30 x 2^-10 = 2^(30 – 10) = 2^20.
Now we have:
(2^20) ÷ (2^-7)
To simplify this, we need the division rule of indices which says:
A^a ÷ A^b = A^(a – b)
Therefore we have:
(2^20) ÷ (2^-7) = 2^[20 – (–7)] = 2^(20+7) = 2^27
Given that Jessica attends summer camp at a distance of four hundred twenty-three and four tenth mile = 
And a detour adds 10 miles to the distance.
That means we need to add 10 miles to the given distance.
So new distance = 423.4 + 10 = 433.4 miles
Hence Jessica needs to travel 433.4 miles for summer camp.
Answer:
0.884
Step-by-step explanation:
6.8x10^2 = 680
1.3x10^-3 = 0.0013
680 X 0.0013 = 0.884