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e-lub [12.9K]
2 years ago
7

A bag contains five white balls and four black balls. Your goal is to draw two black balls. You draw two balls at random. Once y

ou have drawn two balls, you put back any white balls, and redraw so that you again have two drawn balls. What is the probability that you now have two black balls? (Include the probability that you chose two black balls on the first draw.)
Mathematics
1 answer:
Shkiper50 [21]2 years ago
8 0

Answer:

Probabilty of both Black

= 1/6

Step-by-step explanation:

A bag contains five white balls and four black balls.

Total number of balls= 5+4

Total number of balls= 9

Probabilty of selecting a black ball first

= 4/9

Black ball remaining= 3

Total ball remaining= 8

Probabilty of selecting another black ball without replacement

= 3/8

Probabilty of both Black

=3/8 *4/9

Probabilty of both Black

= 12/72

Probabilty of both Black

= 1/6

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All of the following expressions are equal to N except _____. |−N| −(−N) |N| −N
Maksim231197 [3]

Answer:

D. -N

Step-by-step explanation:

Our four given expressions are:

A. |-N|

B. -(-N)

C. |N|

D. -N

The | | symbols represent absolute value, which is the distance from the value within the two lines and 0; essentially since it measures distance, absolute value always outputs a positive value.

In choice A, we have |-N|, which means the distance between -N and 0. Well, the distance will simply be N, which is equal to N. Eliminate A.

In choice B, we have -(-N). Double negatives signal that they will cancel out to become positive, so -(-N) = N. Eliminate B.

In choice C, we have |N|, which means the distance between N and 0. This is clearly just N, so eliminate C.

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<em>~ an aesthetics lover</em>

3 0
2 years ago
Read 2 more answers
A polling organization asked a nation-wide random sample of 1600 new brides (those who got married in the past 2 years) the foll
iren [92.7K]

Answer:

It has millions of tickets. On each ticket is written a number a dollar amount. The exact average and SD are unknown but are estimated from the sample to be $20,000 and $5,000 respectively.

Step-by-step explanation:

Given that:

sample size n = 1600

sample mean \overline x = 20000

standard deviation = 5000

The objective is to choose from the given option about what most closely resembles the relevant box model.

The correct answer is:

It has millions of tickets. On each ticket is written a number a dollar amount. The exact average and SD are unknown but are estimated from the sample to be $20,000 and $5,000 respectively.

However, if draws are made without replacement, the best estimate of the average amount for the bride will be $20,000

Similarly, the standard error for the sample mean = \dfrac{s}{\sqrt{n}}

= \dfrac{5000}{\sqrt{1600}}

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4 0
2 years ago
Match the line segments with their lengths. If necessary, round your answers to the nearest hundredth. PLEASE HELP ME
Stella [2.4K]

Answer:

the fourth one

Step-by-step explanation:

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2 years ago
Annabelle and Navene are multiplying (4275)(4372). Annabelle's Work Navene's Work (4275)(4372) = 42 + 375 + 2 = 4577 (4275)(4372
natta225 [31]

Neither are correct.

Navene has broken the problem up and simply added numbers together to get "4577"

Annabelle is also wrong because whereas she multiplied, she also broke up the numbers in the equation to get "46710"

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7 1
2 years ago
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A candy manufacturer makes two types of special candy, say A and B. Candy A consists of equal parts of dark chocolate and carame
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If we let x as candy A
y as candy B
a as dark chocolate in candy a
b as dark chocolate in candy b
c as caramel
d as walnut
P as profit
we have the equations:
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2b + d = y
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c ≤ 430
d ≤ 210
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This is an optimization problem which involves linear programming. It can be solved by graphical method or by algebraic solution.
P = 285(a + c) + 260(2b +d)
If we assume a = b
Then a = 120, 2b = 240
P = 285(120 + 120) + 260(240 + 120)
P = 162000
candy A should be = 240
candy B should be = 360
6 0
2 years ago
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