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Eddi Din [679]
2 years ago
3

3. A 134.50 g sample of aspirin is made up of 6.03 g of hydrogen, 80.70 g of carbon, and 47.77 g of oxygen. What is the percent

by mass of each element in aspirin?
Chemistry
1 answer:
Oxana [17]2 years ago
8 0

Answer:

The percentage of mass of hydrogen in aspirin is 4.48%

The percentage of mass of carbon in aspirin is 60%

The percentage of mass of oxygen in aspirin is 35.5%

Explanation:

Given that,

Mass of sample of aspirin = 134.50 g

Mass of hydrogen = 6.03 g

Mass of carbon = 80.70 g

Mass of oxygen = 47.77 g

We need to calculate the percentage of mass of hydrogen in aspirin

Using formula for percentage of mass

\text{percentage of mass of hydrogen}=\dfrac{m_{h}}{m_{s}}\times100

Put the value into the formula

\text{percentage of mass of hydrogen}=\dfrac{6.03}{134.50}\times100

\text{percentage of mass of hydrogen}=4.48\%

We need to calculate the percentage of mass of carbon in aspirin

Using formula for percentage of mass

\text{percentage of mass of carbon}=\dfrac{m_{c}}{m_{s}}\times100

Put the value into the formula

\text{percentage of mass of carbon}=\dfrac{80.70}{134.50}\times100

\text{percentage of mass of carbon}=60\%

We need to calculate the percentage of mass of oxygen in aspirin

Using formula for percentage of mass

\text{percentage of mass of oxygen}=\dfrac{m_{o}}{m_{s}}\times100

Put the value into the formula

\text{percentage of mass of oxygen}=\dfrac{47.77}{134.50}\times100

\text{percentage of mass of oxygen}=35.5\%

Hence, The percentage of mass of hydrogen in aspirin is 4.48%

The percentage of mass of carbon in aspirin is 60%

The percentage of mass of oxygen in aspirin is 35.5%

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This is an incomplete question, the table is attached below.

Answer : The correct ranking of the solution from most exothermic to most endothermic will be: A, B and C.

Explanation :

As we know that the intermolecular force of attraction play an important role in the interaction of solute-solute, solute-solvent and solvent solvent solution.

In the solution A, the solute-solute and solvent-solvent interactions are weak. So, their solute-solvent interaction will be strong. That means, the solution will be more exothermic.

In the solution C, the solute-solute and solvent-solvent interactions are strong. So, their solute-solvent interaction will be weak. That means, the solution will be more endothermic.

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Explanation:

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