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2 years ago

briefly discuss the phenomenon of childhood maltreatment in the context of five different psychological perspectives

Physics

1 answer:

Butoxors [25]2 years ago

6 0

Answer:

Child maltreatment or child abuse is a phenomenon of sexual, physical, and/or psychological abuse of children.

Five different psychological perspectives of childhood maltreatment are as follows:

Poverty is one of the biggest cause of childhood maltreatment that impact once psychological health.
Child do not get proper care from their parents.
Childrens are emotionally weak and anything negative thought can depress them.
Lack of communication sometimes make children underconfident.
Social descrimination on the basis of race and gender can impact a child psychological balance.

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Which is NOT a "commonsense" psychological myth?

disa [49]

Answer:A. infants who listen to Mozart are smarter than those that don't.

Explanation: Common Sense is a sound practical judgement of the scheme of things, it can be easily understood as one thinks about life situation.

All other options such as MOST OLDER PEOPLE LIVE SAD AND SOLITARY LIVES ARE CORRECT AS THEY ARE KNOWN TO BE MORE LIKELY TO FALL SICK EASILY.

EATING "COMFORT FOOD" MAKES YOU FEEL HAPPIER IS KNOWN TO BE TRUE AND "COMMONSENSE"

UNLEASHING ANGER CAN MAKE YOU MORE AGGRESSIVE IS A "COMMONSENSE".

only the first option which says infants who listen to Mozart are smarter than those that don't listen to Mozart is not a "commonsense" psychological myth.

6 0

2 years ago

A car moving with constant acceleration covers the distance between two points 60 m apart in 6.0 s. Its speed as it passes the s

BlackZzzverrR [31]

Answer:

The speed in the first point is: 4.98m/s

The acceleration is: 1.67m/s^2

The prior distance from the first point is: 7.42m

Explanation:

For part a and b:

We have a system with two equations and two variables.

We have these data:

X = distance = 60m

t = time = 6.0s

Sf = Final speed = 15m/s

And We need to find:

So = Inicial speed

a = aceleration

We are going to use these equation:

$Sf^2=So^2+(2*a*x)$

$Sf=So+(a*t)$

We are going to put our data:

$(15m/s)^2=So^2+(2*a*60m)$

$15m/s=So+(a*6s)$

With these equation, you can decide a method for solve. In this case, We are going to use an egualiazation method.

$\sqrt{(15m/s)^2-(2*a*60m)}=So$

$15m/s-(a*6s)=So$

$\sqrt{(15m/s)^2-(2*a*60m)}=15m/s-(a*6s)$

$[\sqrt{(15m/s)^2-(2*a*60m)}]^{2}=[15m/s-(a*6s)]^{2}$

$(15m/s)^2-(2*a*60m)}=(15m/s)^{2}-2*(a*6s)*(15m/s)+(a*6s)^{2}$

$-120m*a=-180m*a+36s^{2}*a^{2}$

$0=120m*a-180m*a+36s^{2}*a^{2}$

$0=-60m*a+36s^{2}*a^{2}$

$0=(-60m+36s^{2}*a)*a$

$0=a1$

$\frac{60m}{36s^{2}} = a2$

$1.67m/s^{2}=a2$

If we analyze the situation, we need to have an aceleretarion greater than cero. We are going to choose a = 1.67m/s^2

After, we are going to determine the speed in the first point:

$Sf=So+(a*t)$

$15m/s=So+1.67m/s^2*6s$

$15m/s-(1.67m/s^2*6s)=So$

$4.98m/s=So$

For part c:

We are going to use:

$Sf^2=So^2+(2*a*x)$

$(4.98m/s)^2=0^2+(2*(1.67m/s^2)*x)$

$\frac{24.80m^2/s^2}{3.34m/s^2}=x$

$7.42m=x$

5 0

2 years ago

What is the initial velocity of the object represented by the graph? ___m/s Graph:

Alex17521 [72]

Answer:

On a velocity-time graph… slope is acceleration. the "y" intercept is the initial velocity. when two curves coincide, the two objects have the same velocity at that time.

4 0

2 years ago

Read 2 more answers

3. In 1989, Michel Menin of France walked on a tightrope suspended under a

Tamiku [17]

Answer: 80m

Explanation:

Distance of balloon to the ground is 3150m

Let the distance of Menin's pocket to the ground be x

Let the distance between Menin's pocket to the balloon be y

Hence, x=3150-y------1

Using the equation of motion,

V^2= U^s + 2gs--------2

U= initial speed is 0m/s

g is replaced with a since the acceleration is under gravity (g) and not straight line (a), hence g is taken as 10m/s

40m/s is contant since U (the coin is at rest is 0) hence V =40m/s

Slotting our values into equation 2

40^2= 0^2 + 2 * 10* (3150-y)

1600 = 0 + 63000 - 20y

1600 - 63000 = - 20y

-61400 = - 20y minus cancel out minus on both sides of the equation

61400 = 20y

Hence y = 61400/20

3070m

Hence, recall equation 1

x = 3150 - 3070

80m

I hope this solve the problem.

6 0

2 years ago

A wheel completes 5.6 revolutions in 8 seconds.

nevsk [136]

Answer:

$86.15\pi rad/min$

Explanation: Angular velocity is the number of revolutions made per unit time.

We convert the number of revolutions to radians and the time given in seconds to minutes,

Given;

$1rev=2\pi rad\\therefore\\5.6rev=5.6*2\pi rad\\= 11.2\pi rad$

Also,

60s = 1 min

hence

$8s=\frac{8}{60}min\\=0.13min$

We now divide the number of revolution in radians by the time in minutes.

$\omega =\frac{11.2\pi}{0.13min}\\\omega=86.15\pi rad/min$

5 0

2 years ago

Read 2 more answers