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MA_775_DIABLO [31]
2 years ago
9

The total cost C (in dollars) of playing an online game is given by the literal equation C = 30x + 50, where x is the number of

months you play the game. Solve the equation for x. How many months do you play the game when you spend $170? $260?
Mathematics
1 answer:
adelina 88 [10]2 years ago
8 0

Answer:

4 months and 7 months

Step-by-step explanation:

C = 30x + 50

C is cost so when we spend $170 we can solve for x.

$170 = 30x + 50

170 - 50 = 30x + 50 - 50

170 - 50 = 30x

120 = 30x

120/30 = 30x/30

120/30 = x

4 = x

So he has played 4 months when he spends $170

C is cost so when we spend $260 we can solve for x.

$260 = 30x + 50

260 - 50 = 30x + 50 - 50

260 - 50 = 30x

210 = 30x

210/30 = 30x/30

210/30 = x

7 = x

So he has played 7 months when he spends $260

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Answer:

see below

Explanation:

There are many ways of writing a verbal expression for the given algebraic expression.

Some examples are:

a number c plus twice a number da number c added to twice a number dc added to the product of 2 and d the product of 2 and d increased by c twice a number d increased by cthe sum of c and twice d

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Isosceles △ABC (AC=BC) is inscribed in the circle k(O). Prove that the tangent to the circle at point C is parallel to AB .
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Explanation:

Let M be the midpoint of AB. Then CM is the perpendicular bisector of AB. As such, center O is on CM, and OC is a radius (and CM). The tangent is perpendicular to that radius (and CM), so is parallel to AB, which is also perpendicular to CM.

If you need to go any further, you can show that triangles CMA and CMB are congruent, so (linear) angles CMA and CMB are congruent, hence both 90°.

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The density of granite is about 2.75 grams per cubic centimeter. Suppose you have a granite countertop for a kitchen that is 1 m
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Answer:

330\ kg

Step-by-step explanation:

Remember that

1 kg=1,000 g

1 m= 100 cm

The volume of the granite countertop in cubic centimeters is equal to

V=(100)(300)(4)\ cm^{3}

The density in kg per cubic centimeter is equal to

D=2.75(\frac{1}{1,000}) \frac{kg}{cm^{3}}

Multiply the density by the volume

2.75(\frac{1}{1,000})(100)(300)(4)

2.75(120)=330\ kg

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Melissa buys 212 pounds of salmon and 114 pounds of swordfish. She pays a total of $31.25, and the swordfish costs $0.20 per pou
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Step-by-step explanation:

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A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st
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Answer:

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

p_v =2*P(z>1.413)=0.158  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

Step-by-step explanation:

Data given and notation  

\bar X=5.0611 represent the sample mean

\sigma=0.2803 represent the population standard deviation for the sample  

n=42 sample size  

\mu_o =5 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 5, the system of hypothesis would be:  

Null hypothesis:\mu = 5  

Alternative hypothesis:\mu \neq 5  

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>1.413)=0.158  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

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