Use the table and the data provided to analyze the following data. During gym class, the pulse rate was recorded for 19 students
before and after an exercise warm-up. The pulse rates are listed below. Pulse before Exercise Pulse after Exercise 67 87 67 88 67 89 68 89 71 91 72 93 72 93 75 95 77 96 77 97 79 98 81 98 85 101 87 105 87 105 91 119 97 125 103 125 121 147 Part A: Create a stemplot for each set of data. Justify your reasoning for split or nonsplit stems. (10 points) Part B: Compare and contrast the two data sets. Justify your answer using key features of the data (shape, outliers, center, and spread). (10 points) just a little confused on how to set it up
1 answer:
Answer:
Part A
Please see attached the required stem and leaf plot
For the stem and leaf plot, the nonsplit system is used because of clarity for analysis
Part B:
From the shape of the stem and leaf plot we have that there is an average increase of pulse rate of 20 pulses in all the 19 students after the exercise
The shape of the plot is relatively the same for the before and after exercise save for the decrease in the third to the last row by one and the increase in the second to the last roe by one student
The spread remained relatively constant in both cases with the most being in the 60s range having 7 students in the before exercise and the 80s range having 8 students in the after exercise leaf plot.
Step-by-step explanation:
The given data are;
67 87
67 88
67 89
68 89
71 91
72 93
72 93
75 95
77 96
77 97
79 98
81 98
85 101
87 105
87 105
91 119
97 125
103 125
121 147
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Answer:
A and C
Step-by-step explanation:
To determine which events are equal, we explicitly define the elements in each set builder.
For event A
A={1.3}
for event B
B={x|x is a number on a die}
The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as
B={1,2,3,4,5,6}
for event C
Hence the set c is C={1,3}
and for the set D {x| x is the number of heads when six coins re tossed }
In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6
Hence the set D can be expressed as
D={0,1,2,3,4,5,6}
In conclusion, when all the set are compared only set A and set C are equal
Answer:
8r^4
Step-by-step explanation:
Answer:
(1) Correct option (A).
(2) The probability that Aadi will get Tails is 0.40.
Step-by-step explanation:
The information provided is:
- Eric throws a biased coin 10 times. He gets 3 tails.
- Sue throw the same coin 50 times. She gets 20 tails.
The probability of tail in both cases is:
Here,
P (T|E) implies the probability of tail in case of Eric's experiment.
P (T|S) implies the probability of tail in case of Sue's experiment.
(1)
Now, it is given that Aadi is going to throw the coin once.
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
In this case we need to compute the probability of Aadi getting Tails in a single toss.
As Sue uses a larger number of trials in the experiment, i.e. n = 50 > 30 times, according to the Central limit theorem, Sue's estimate is best because she throws it .
Thus, the correct option is (A).
(2)
As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:
Thus, the probability that Aadi will get Tails is 0.40.