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kolezko [41]
2 years ago
14

Tag groups can be nested up to ____ levels deep, with up to _______ tag subgroups under a single parent.

Computers and Technology
1 answer:
zepelin [54]2 years ago
3 0
Is it a multiple choices problem
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You are given an array x of string elements along with an int variable n that contains the number of elements in the array. You
Slav-nsk [51]

Answer:

The code to this question can be given as:

Code:

int i,j,count_previous=0,count_next=0; //define variable

for (j=0; j<n; j++) //loop for array

{

if (x[0]==x[j]) //check condition

{

count_previous++; //increment value by 1.

}

}

for (i=0; i<n; i++) //loop

{

for (j=0; j<n; j++)

{

if (x[i]==x[j]) //check condition

{

count_next++; //increment value by 1.

}

}

if (count_previous>count_next) //check condition

{

mode=x[i-1];

}

else

{

mode=x[i];

count_previous=count_next; //change value.

count_next= 0 ; //assign value.

}

}

Explanation:

In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.

8 0
2 years ago
Write the definition of a class Telephone. The class has no constructors, one instance variable of type String called number, an
balu736 [363]

Answer:

The definition of a class Telephone is given as  

public class Telephone // class telephone

{

String number; // variable  number of type string

static int quantity = 250; // variable  quantity  of type int

static double total = 1565.92;  // variable  total  of type double

}

Explanation:

Following is the description of Statement

  • Create a class "Telephone" by using the keyword class.In that class we declared data member .
  • We declared a variable "number" of type "string" which has no constructor.
  • We declared a variable  "quantity" of type "int" which is a static type variable. The static type variable retains the value during the program execution.
  • We declared a variable  "total" of type "double" which is a static type variable. The static type variable retain the value during the program execution .
5 0
2 years ago
Lance is at a bus station. His friend is using the ATM machine to withdraw some money. Lance notices a stranger deceptively watc
Blababa [14]

Answer:

The person watching Lances friend typing the ATM pin is an example of <u>"shoulder browsing"</u> and Lances friend should <u>"Change the ATM pin."</u>

<u />

<u>I hope this is the answer you were looking for!</u>

8 0
2 years ago
Read 2 more answers
Suppose your company has decided that it needs to make certain busy servers faster. Processes in the workload spend 60% of their
vekshin1

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = \frac{1}{(1-f)+ \frac{f}{k} }      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.6)+ \frac{0.6}{k} }  

solve we get

k = 1.5

so we can say  CPU need 50% much faster

and

when f = 0.4 and S = 125 %

put the value in equation 1

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.4)+ \frac{0.4}{k} }  

solve we get

k = 2

so here disk need 100% much faster

7 0
2 years ago
Float_abs - return bit-level equivalent of absolute value of f for * floating point argument f. * both the argument and result a
olga_2 [115]

#include <stdio.h>

int main(void) {

            // your code goes here

            //unsigned a =float_times_four(0x80000000);

            unsigned float_times_four(unsigned uf){

                unsigned expn = (uf >> 23) & 0xFF;

                printf(expn);

                unsigned sign = uf & 0x80000000;

                unsigned frac = uf & 0x007FFFFF;

                if(expn == 255 ||(expn == 0 && frac ==0))

                    return uf;

                if(expn){

                    expn<<2;

                }else if(frac == 0x007FFFFF){

//here 0x7FFFFF given by you that is wrong you place this 0x007FFFFF will excute

                    frac>>2;

                    expn<<2;

                }else{

                    frac<<=2;

                }

return (sign) | (expn <<23) | (frac);

            }

            return 0;

}

3 0
2 years ago
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