Question

The pilot of a helicopter drops a lead brick from a height of 500 m. (assume no air resistance and g~10 m/s2) roles Evalu How long does it take to reach the ground?

Answer 1

Answer:

The  value  is  $t = 10 \ s$

Explanation:

From the question we are told that

  The  height is  $h = 500 \ m$

  The acceleration is  $g = 10 \ m/s$

 

Generally from the second equation of motion we have that

    $h = ut + \frac{1}{2} a t^2$

Here  the initial velocity u =  0  m/s  given that the stone started from rest

       So

            $500 = 0 (t) +0.5 * (10) t^2$

=>         $t = 10 \ s$