Answer:
Explanation:
given data:
flow Q = 9 m^{3}/s
velocity = 8 m/s
density of air = 1.18 kg/m^{3}
minimum power required to supplied to the fan is equal to the POWER POTENTIAL of the kinetic energy and it is given as
here is mass flow rate and given as
Putting all value to get minimum power
Actually Welcome to the concept of Efficiency.
Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%
The efficiency is => 22% => 22/100.
so we get as,
E = W(output) /W(input)
hence, W(output) = E x W(input)
so we get as,
W(output) = (22/100) x 2.2 x 10^7
=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7
hence, W(output) = 4.84 x 10^6 J
The useful work done on the mass is 4.84 x 10^6 J
Answer:
The gas was Hexane
Explanation:
taking the diference between the mass of the flask and the final mass qe can calculate the mass of liquid injected (assuming none escaped the flask):
with the volume of the flask we can get the density of the gas at the indicated pressure and temperature:
From the ideal gases law we have that the density can be calculated as:
Where R is the ideal gases constant = , and M the molecular weight of the fluid. Solving for M:
Note that the temperature is computed in Kelvin T= 18+273=291K
The gas with the closer molar mass is Hexane