This table shows Wayne’s weight on four different planets. Planet Wayne’s weight (pounds) Mars 53 Neptune 159 Venus 128 Jupiter
1 answer:
The correct order is (in decreasing order of gravity strength)
Jupiter - Neptune - Venus - Mars
In fact, Wayne's weight on each planet is given by
where m is Wayne's mass, which is a constant value, and g is the gravity strength at the surface of the planet. Therefore, the Wayne's weight W on each planet is directly proportional to the gravity strength of that planet: so the planet with the strongest gravity is the one where Wayne's weight is the greatest (Jupiter, 333 pounds), followed by Neptune (159), Venus (128) and Mars (53).
Jupiter - Neptune - Venus - Mars
In fact, Wayne's weight on each planet is given by
where m is Wayne's mass, which is a constant value, and g is the gravity strength at the surface of the planet. Therefore, the Wayne's weight W on each planet is directly proportional to the gravity strength of that planet: so the planet with the strongest gravity is the one where Wayne's weight is the greatest (Jupiter, 333 pounds), followed by Neptune (159), Venus (128) and Mars (53).
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Answer:
b) TA = TB = TC
Explanation:
- When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
- During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
- The equilibrium condition will be reached when the following equation be met:
- Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for Tfin, as follows:
- So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
- When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
- So, option b) is the right one.