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vitfil [10]
2 years ago
5

A 0.2-kg steel ball is dropped straight down onto a hard, horizontal floor and bounces straight up. The ball's speed just before

and just after impact with the floor is 10 m/s. Determine the magnitude of the impulse delivered to the floor by the steel ball.
Physics
2 answers:
nadya68 [22]2 years ago
7 0

Answer:

Explanation:

Given

mass of steel ball m=0.2\ kg

initial speed of ball u=10\ m/s

Final speed of ball v=-10\ m/s (in upward direction)

Impulse imparted is given by change in the momentum of object

therefore impulse J is given by

J=\Delta P

\Delta P=m(v-u)

\Delta P=0.2(-10-10)

\Delta =-4\ N-s

so magnitude of Impulse =4 N-s

MAVERICK [17]2 years ago
4 0

Answer:

4 N s

Explanation:

mass, m = 0.2 kg

initial velocity, u = - 10 m/s (downward )

final velocity, v = + 10 m/s (upwards)

Impulse is defined a the change in momentum .

Impulse = m ( v - u)

Impulse = 0.2 ( 10 + 10)

Impulse = 4 N s

thus, the impulse is 4 N s .

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2 years ago
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What is the formula that can be used to find velocity if kinetic energy and mass are known?
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The formula for kinetic energy is \frac{1}{2}m\Delta v^2. Thus, the equation for velocity is v=   \sqrt{ \frac{2TotalKineticEnergy}{m} }. 
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If you accidentally touch the "hot" wire connected to the 120 V line, how much current will pass through your body?
Sav [38]
<h2>Complete Question:</h2>

You are on an aluminum ladder that is standing on the ground, trying to fix an electrical connection with a metal screwdriver having a metal handle. Your body is wet because you are sweating from the exertion; therefore, it has a resistance of 1.60 kΩ .

(a) If you accidentally touch the "hot" wire connected to the 120 V line, how much current will pass through your body?

(b) How much electrical power is delivered to your body?

<h2>Answer:</h2>

(a) 0.075A

(b) 9W

<h2>Explanation:</h2>

The voltage (V) passing across or supplied to a body is directly proportional to the current (I) flowing through the body as stated by Ohm's law. i.e

V ∝ I

=> V = I x R                 ----------------------(i)

Where;

R = constant of proportionality called resistance of the body

(a) As stated in the question;

The body is wet and thus will conduct electricity and has the following;

V = voltage supplied = 120V

R = resistance of the wet body = 1.60kΩ = 1.6 x 1000Ω = 1600Ω

Substitute these values into equation(i) as follows;

120 = I x 1600

Solve for I;

I = \frac{120}{1600}

I = 0.075A

Therefore the amount of current that will pass through your body is 0.075A

(b) Electrical power(P), which is commonly measured in Watts(W), delivered to a body is the product of the current(I) and voltage (V) supplied to the body. i.e

P = I x V           ---------------------(ii)

Where;

I = 0.075A   [as calculated above]

V = 120V     [given in the question]

Substitute these values into equation (ii) as follows;

P = 0.075 x 120

P = 9W

Therefore, the electric power delivered to your body is 9W

7 0
2 years ago
A bucket of water experiencing a gravitational force of 525 N is pulled from a water well. Net force in the Y direction is 45 N
vivado [14]

Answer:

T = 570 N

Explanation:

Given that,

The gravitational force acting on a bucket of water = 525 N

Net force in the Y direction is 45 N

We need to find the magnitude of the force of tension. It can be calculated as :

45 = T - 525

T = 525 + 45

T = 570 N

Hence, the force of tension is 570 N.

7 0
2 years ago
When charges qa, qb, and qc are placed respectively at the corners a, b, and c of a right triangle, the potential at the midpoin
earnstyle [38]

Answer:

8v

Explanation:

First we apply super position principle

Vt= v1 + v2+ v3

Remove qa

But vt= 20v

So V = v2+v3

V1= 20-15

= 5v

Remove qb

V= v1+v3

V=8v

So the potential when qa and qc are remove is the potential due to qb

Which is 8v

7 0
2 years ago
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