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vitfil [10]
2 years ago
5

A 0.2-kg steel ball is dropped straight down onto a hard, horizontal floor and bounces straight up. The ball's speed just before

and just after impact with the floor is 10 m/s. Determine the magnitude of the impulse delivered to the floor by the steel ball.
Physics
2 answers:
nadya68 [22]2 years ago
7 0

Answer:

Explanation:

Given

mass of steel ball m=0.2\ kg

initial speed of ball u=10\ m/s

Final speed of ball v=-10\ m/s (in upward direction)

Impulse imparted is given by change in the momentum of object

therefore impulse J is given by

J=\Delta P

\Delta P=m(v-u)

\Delta P=0.2(-10-10)

\Delta =-4\ N-s

so magnitude of Impulse =4 N-s

MAVERICK [17]2 years ago
4 0

Answer:

4 N s

Explanation:

mass, m = 0.2 kg

initial velocity, u = - 10 m/s (downward )

final velocity, v = + 10 m/s (upwards)

Impulse is defined a the change in momentum .

Impulse = m ( v - u)

Impulse = 0.2 ( 10 + 10)

Impulse = 4 N s

thus, the impulse is 4 N s .

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7. A local sign company needs to install a new billboard. The signpost is 30 m tall, and the ladder truck is parked 24 m away fr
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<h2>Solution :</h2>

Here ,

• Height of sign post = 30 m

• Distance between signpost and truck = 24 m

Let the

• Top of signpost = A

• Bottom of signpost = B

• The end of truck facing sign post be = C

Now as we can clearly imagine that the ladder will act as an hypotenuse to the Triangle ABC .

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2 years ago
(a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.500 - μC charge and flies due west at a sp
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(a) 2.64\cdot 10^{-8} N north

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F=qvB sin \theta

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v = 660 m/s is the velocity

B=8.00\cdot 10^{-5} T is the magnitude of the magnetic field

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Substituting,

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(b) Not negligible

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W=mg=(80000)(9.8)=784,000 N

As we can see, this is several orders of magnitude bigger than the magnetic force calculated at point (a), so the effects of the magnetic force are negligible.

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