<h2>Answer</h2>
Gravitational potential energy of the textbook-Earth system relative to the desk = 98 N/m
<h2>Explanation</h2>
Given that,
Mass of history book = 8kg
height of book from ground = 1.25m
acceleration due to gravity = 9.8m/s²
<h3>gravitational potential energy formula</h3><h2>GPE = Fg⋅h</h2><h2>GPE = mgh</h2>
where ,
m = mass of object(book)
g = acceleration due to gravity
h = the altitude of the object.
GPE = 8(9.8)(1.25)
= 98 N/m
So, gravitational potential energy of the textbook-Earth system relative to the desk = 98 N/m
Answer:
The Frequency of the wave is 0.2Hertz
The period is 2seconds
Explanation:
We are asked to find the frequency and period
Frequency is the number of oscillations completed in one seconds
If five waves were made from the same source in 10 seconds, hence;
Frequency = number of oscillation/Time
Frequency = 5/10
Frequency = 0.5Hertz
Next is to get the period
Period = 1/Frequency
Period = 1/0.5
Period = 2seconds
Dab
10. <span>A block with mass m = 6.2 kg is attached to two springs with spring constants kleft = 31.0 N/m and kright = 49.0 N/m. The block is pulled a distance x = 0.2 m to the left of its equilibrium position and released from rest
</span>
Answer:
Explanation:
Let v be the linear velocity , ω be the angular velocity and I be the moment of inertia of the the puck.
Kinetic energy ( linear ) = 1/2 mv²
Rotational kinetic energy = 1/2 I ω²
I = 1/2 m r² ( m and r be the mass and radius of the puck )
Rotational kinetic energy = 1/2 x1/2 m r² ω²
= 1/4 m v² ( v = r ω )
Total energy
= Kinetic energy ( linear ) + Rotational kinetic energy
= 1/2 mv² + 1/4 m v²
= 3/4 mv²
rotational K E / Total K E = 1/4 m v² / 3/4 mv²
= 1 /3
So 1 /3 rd of total energy is rotational K E.
A goes with 2 and B goes with 1.
