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HACTEHA [7]
2 years ago
10

An insulin drip is mixed as 500.0 units in 250.0 mL Normal Saline (NS). Calculate the drip rate in mL/h needed to deliver 4.0 un

its/h?
Chemistry
1 answer:
olasank [31]2 years ago
3 0

Answer:

Drip rate = 2 ml/h

Explanation:

Given:

Amount of insulin = 500 unit

Amount of saline = 250 ml

Required infusion rate = 4.0 units/h

Find:

Drip rate

Computation:

Concentration = Units of insulin / Volume of saline

= 500 / 250

Concentration = 2 units/ml

Drip rate = Infusion rate / concentration

Drip rate = 4 / 2

Drip rate = 2 ml/h

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When you apply heat energy to a substance, where does the energy go? Think about the law of conservation of energy.
MAVERICK [17]

The energy is transformed into kinetic energy which makes the substance to move. The law of conservation of energy which is the first law of thermodynamics states that in a closed system energy can neither be created nor destroyed but can change from one form to another

7 0
2 years ago
A bottle containing 1,665 g of sulfuric acid (H2SO4, 98.08 g/mol) was spilled in a laboratory. The emergency spill kit contained
Tamiku [17]

Answer:

A. Yes, there is more than enough sodium carbonate.

Explanation:

Hello,

In this case, based on the given reaction which is:

H_2SO_4(aq) + Na_2CO_3(s) \rightarrow  Na_2SO_4(aq) + CO_2(g) + H_2O(l)

By stoichiometry, one computes the grams of sodium carbonate that will neutralize 1,665 g of sulfuric acid as shown below:

1,665gH_2SO_4*\frac{1molH_2SO_4}{98.08gH_2SO_4}*\frac{1molNa_2CO_3}{1molH_2SO_4} *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}*\frac{1kgNa_2CO_3}{1000gNa_2CO_3}\\m_{Na_2CO_3}=1.80gNa_2CO_3

Thus, the available mass is 2.0 kg so 0.2 kg are in excess, therefore: A. Yes, there is more than enough sodium carbonate.

Best regards.

5 0
2 years ago
Some household cleaners come in concentrations stronger than necessary for basic cleaning jobs. Jeremy followed the instructions
VashaNatasha [74]

Answer:

no he just repeated the steps and made more of the same cleaner my guy

Explanation:

5 0
2 years ago
in a candy factory, the nutty chocolate bars contain 22.0% by mass pecans. If 5.0 kg of pecans were used for candy last Tuesday,
zysi [14]
22.0 is the same as saying that in 100 grams of a chocolate bar, there are 22.0 grams of pecans. or to make it easier because of this problem- 100 Kilograms of a chocolate bar, there is 22.0 Kg of pecans. we can use this as a conversion factor (what is used to convert a value to another value. 

conversion factor---> 22.0 kg of pecan= 100 kg of chocolate bar
Note: remember this, what you are converting from goes in the denominator, what you converting to goes in the numerator. 

5.0 Kg of pecan (100 Kg of chocolate bar/ 22.0 Kg of pecan)= 23 Kg of chocolate bar


7 0
2 years ago
The Lewis structure for CO2 has a central The Lewis structure for C O 2 has a central blank atom attached to blank atoms.
kirza4 [7]

Answer:

See the explanation

Explanation:

1) The Lewis structure for  CO_2 has a central Carbon<em> </em>atom attached to Oxygen atoms.

In the CO_2  we will have a structure:  O=C=O the <u>central atom</u> "carbon" we will have <u>2 sigma bonds and 2 pi bonds</u>, therefore, we have an <u>Sp hybridization</u>. For O we have <u>1 pi and 1 sigma bond</u>, therefore, we have an <u>Sp2 hybridization</u>.

2) These atoms are held together by <u>double bonds.</u>

<u></u>

Again in the structure of CO_2: O=C=O we only have double bonds.

3. Carbon dioxide has a Carbon dioxide has a <u>Linear</u> electron geometry.

Due to the double bonds we have to have a linear structure because in this geometry the atoms will be further apart from each other.

4. The carbon atom is <u>Sp</u> hybridized.

We will have for carbon 2 pi bonds, so we will have an <u>Sp</u> hybridization.

5. Carbon dioxide has two Carbon dioxide has two C(p) - O(p) π bonds and two C(sp) - O(Sp2) σ bonds.

(See figures)

Figure 1: Carbon hybridization

Figure 2: Oxygen hybridization

6 0
2 years ago
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