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Ronch [10]
2 years ago
13

Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(

s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 14 seconds. Use complete sentences to support your answer. (3 points)

Mathematics
1 answer:
Allushta [10]2 years ago
7 0

Answer:

A). interval 0 ≤ x ≤ 2

B). interval 2 ≤ x ≤ 4

C). interval 8 ≤ x ≤ 10

D). h(14) = 0

Step-by-step explanation:

Part A.

In the interval 0 ≤ x ≤ 2, height of the water balloon is increasing.

Part B.

In the interval 2 ≤ x ≤ 4, height of the water balloon is constant.

Part C.

In the interval 8 ≤ x ≤ 10, height of the water balloon is decreasing the fastest.

Slope of the line between x = 8 and x = 10 is the maximum.

Part D.

Since at x = 10 height of the water balloon is h = 0, therefore, at any moment after x = 10 seconds height of the balloon will remain zero.

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Answer:

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8 0
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James is four years younger than Austin. If three times James' age is increased by the square of Austin's age, the result is 28.
lara31 [8.8K]
Let's use J for James's age and A for Austin's age. The equations are:

J = A - 4
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Just plug (A - 4) in the place of J in the second equation. This gives you:

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