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2 years ago

Describe how to use Le Chatelier’s principle to predict the possible ways a chemical system can respond to changes.

2 answers:

7 0

For ED you can put what happens to the equilibrium when common ions are added or you can put what happens to the equilibrium when the concentration of the reactants increases or decreases

Andre45 [30]2 years ago

4 0

Le Chatelier's principle simply explains how equilibria change as you change the conditions of a reaction. If you have a reaction that is at equilibrium lets say (A + 2B <--> C + D) by removing C or D we can drive the reaction forward and products more products. I can provide a more in-depth description if needed.

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Given the following data, determine the rate constant of the reaction 2NO(g) +Cl2(g) --> 2NOCl(g) Experiment [NO] (M) [Cl2] (

andrew-mc [135]

Answer:

k = 2.647 x 10-2 M-2 s-1

Explanation:

2NO(g) +Cl2(g) --> 2NOCl(g)

Experiment [NO] (M) [Cl2] (M) Rate (M/s)

1 0.0300 0.0100 3.4 x 10-4

2 0.0150 0.0100 8.5 x 10-5

3 0.0150 0.0400 3.4 x 10-4

Frrom experiments 1 and 3;

Reducing the concentration of NO by a factor of 2 decreases the rate of the reaction by a factor of 4. This means the reaction is second order with respect to NO.

From experiments 2 and 3:

Increasing the concentration of Cl2 by a factor of 4 increases the rate by a factor of 4. This means the reaction is first order with respect to Cl2

The rate equation is given as;

Rate = k [NO]² [Cl2]

From experiment 1;

k = [NO]² [Cl2] / Rate

k = 0.0300² * 0.0100 / 3.4 x 10-4

k = 2.647 x 10-2 M-2 s-1

7 0

2 years ago

Question 4: Which members of an ecosystem are part of the energy flow?

Vanyuwa [196]

Answer:

The answer is A (number 1)

5 0

2 years ago

What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2

LekaFEV [45]

Molar mass CaCl₂ = 111.0 g/mol

number of moles:

n = mass of solute / molar mass

n = 85.3 / 111.0

n = 0.7684 moles of CaCl₂

M = n / V

0.788 M = <span>0.7684 / V
</span>
V = 0.7684 / 0.788

V = 0.97512 L

hope this helps!

3 0

2 years ago

Convert 2.0 M of Phenobarbital sodium (MW: 254 g/mole) solution in water into % w/v and ratio strengths.

Travka [436]

Answer:

The concentration is 50,8 % w/v and radio strengths = 1,96.

Explanation:

Phenobarbital sodium is a medication that could treat insomnia, for example.

2,0 M of Phenobarbital sodium means 2 moles in 1L.

The concentration units in this case are %w/v that means 1g in 100 mL and ratio strengths that means 1g in <em>r</em> mL. Thus, 2 moles must be converted in grams with molar weight -254 g/mole- and liters to mililiters -1 L are 1000mL-. So:

2 moles × $\frac{254 g}{1 mole}$ = 508 g of Phenobarbital sodium.

1 L × $\frac{1000 mL}{ 1 L}$ = 1000 mL of solution

Thus, % w/v is:

$\frac{508 g}{1000 mL}$ × 100 = 50,8 % w/v

And radio strengths:

$\frac{1000 mL}{508 g}$ = 1,96. Thus, you have 1 g in 1,96 mL

I hope it helps!

5 0

2 years ago

Calculate the radius ratio for NaBr if the ionic radii of Na + and Br − are 102 pm and 196 pm , respectively. radius ratio: Base

Fudgin [204]

Answer : The expected coordination number of NaBr is, 6.

Explanation :

Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.

This is represented by,

$\frac{r_{cation}}{r_{anion}}$