The correct answer is 36 miles per hour
Explanation:
To find the average speed, the first step is to find the total time and the total distance Lucy covered because the formula for average speed is the total distance divided into the total time.
Total Distance
It is known Lucy covered 2/3 of the total distance first, and then she completed the remaining distance (60 miles). According to this, the last distance or 60 miles represents 1/3 of the total distance.
(Total distance)
Also, if 60 miles is equivalent to 1/3 this number can be used to find the total distance. In this case, just multiply 60 by 3 = 180 miles as 60 is one-third.
This means the total distance is 180 miles
Total Time
It is known the first part of this journey took 3 hours and the second took 2 hours. This means the total time was 5 hours (3 + 2 = 5)
Find the average speed
Answer:
Explanation:
Given that
Constant rate of leak =R
Mass at time T ,m=RT
At any time t
The mass = Rt
So the total mass in downward direction=(M+Rt)
Now force equation
(M+Rt) a =P- (M+Rt) g
We know that
This is the velocity of bucket at the instance when it become empty.
Answer:
(a) 2.8 V
(b) 5.6 V
(c) 9.8 V
Explanation:
Given:
Frequency of the generator (f) = 1300 Hz)
Terminal voltage (V) =12.0 V
Resistance of resistor (R) = 14.0 Ω
Capacitance of capacitor (C) = 4.40 μF = 4.40 × 10⁻⁶ F
Inductance of the inductor (L) = 6.00 mH = 6.00 × 10⁻³ H
In order to find the voltages across each, we first need to find the reactance and impedance.
Reactance of the inductor is given as:
Reactance of the capacitor is given as:
Now, impedance is given as:
Current across the circuit is given as:
As resistor, capacitor and inductor are connected in series, the current across each of them is same and equal to total current in the circuit.
(a)
Voltage across the resistor is given as:
Therefore, the voltage across resistor is 2.8 V.
(b)
Voltage across the capacitor is given as:
Therefore, the voltage across the capacitor is 5.6 V.
(c)
Voltage across the inductor is given as:
Therefore, the voltage across the inductor is 9.8 V.