f(x)=x^2+12x+26
Vertex form of f(x) = a(x-h)^2 +k
We change f(x) into vertex form using completing the square method
We take half of square of middle term
middle term is 12
Half of square of 12 is then 6^2 = 36
Add and subtract 36 to complete the square
The vertex form
Answer:
y = 16x/65
Step-by-step explanation:
Given:
Triangle ABE is similar to triangle ACD. AED and ABC are straight lines
EB and DC are parallel
The area of quadrilateral BCDE = xcm²
The area of triangle ABE = ycm²
Find attached the diagram from the above information.
In similar triangles, the ratio of their corresponding angles are equal.
Also, the ratio of the area of the two triangles = square of ratio of the corresponding sides of the two triangles.
Area ∆ACD/area of ∆ABE = (DC/EB)²
Area ∆ACD/area of ∆ABE = [(area of quadrilateral BCDE +
area of ∆ABE)]/(area of ∆ABE)
(x+y)/y = (DC/EB)²
(x+y)/y = (9/4)²
x+y = (81/16)y
x = (81/16)y - y
x = (81y - 16y)/16
x = 65y/16
Making y subject of formula
16x = 65y
y = 16x/65
An expression for y in terms of x:
y = 16x/65
Let x represent number of bracelets and y represent number of necklaces.
We have been given that a jeweler made 7 more necklaces than bracelets. This means that number of necklaces will be . We can represent this information in an equation as:
We have been given that the amount of gold in each bracelet is 6 grams, so amount used for x bracelets would be grams.
We are also told that the amount of gold in each necklace is 16 grams, so amount used for y necklaces would be grams.
Since the jeweler used 178 grams of gold, so we will equate the amount of gold used in x bracelets and y necklaces with 178 as:
Therefore, our required system of equations would be: