8. Derek was observing the change in water levels in his fish pond. The table below show the change in water levels of the fish
pond on different dates. DATE WATER LEVEL CHANGE (inches) August 25 -0.75 September 8 3 -1- 8 September 22 2.5 1 October 6 2 October 20 7. 1 8 CLEAR ALL Based on data in the table, what was the total change, in inches, of the water level in the fish pond from August 25 to October 20? whats the answer
1 answer:
Answer:
H. 2 3/4
Step-by-step explanation:
- DATE >> WATER LEVEL CHANGE (inches)
- August 25 >> -0.75
- September 8 >> -1 3/ 8
- September 22 >> 2.5
- October 6 >> -1/2
- October 20 >> 1 7/8
<u>Total change:</u>
- 1 7/8 - (-0.75) =
- 1+ 7/8 + 3/4 =
- 1 + 7/8 + 6/8 =
- 1 + 13/8 =
- 1+ 1 5/8 =
- 2 5/8
The closest answer option is H. 2 3/4
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Answer:
0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean 490 mg and variance of 400.
This means that
What is the probability that a randomly selected pill contains at least 500 mg of minerals?
This is 1 subtracted by the p-value of Z when X = 500. So
has a p-value of 0.6915.
1 - 0.6915 = 0.3085
0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals