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OverLord2011 [107]
2 years ago
8

8. Derek was observing the change in water levels in his fish pond. The table below show the change in water levels of the fish

pond on different dates. DATE WATER LEVEL CHANGE (inches) August 25 -0.75 September 8 3 -1- 8 September 22 2.5 1 October 6 2 October 20 7. 1 8 CLEAR ALL Based on data in the table, what was the total change, in inches, of the water level in the fish pond from August 25 to October 20? whats the answer
​

Mathematics
1 answer:
Alla [95]2 years ago
8 0

Answer:

H. 2 3/4

Step-by-step explanation:

  • DATE                         >> WATER LEVEL CHANGE (inches)
  • August 25                  >>  -0.75
  • September 8              >>  -1 3/ 8
  • September 22            >>  2.5
  • October 6                    >>  -1/2
  • October 20                 >>  1 7/8

<u>Total change:</u>

  • 1 7/8 - (-0.75) =
  • 1+ 7/8 + 3/4 =
  • 1 + 7/8 + 6/8 =
  • 1 + 13/8 =
  • 1+ 1 5/8 =
  • 2 5/8

The closest answer option is H. 2 3/4

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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
2 years ago
First, she needs to find her resting heart rate by counting her pulse for one minute immediately after she wakes up for 5 days i
andreyandreev [35.5K]

Answer:

63

Step-by-step explanation:

She finds her average resting heart rate to be 62 after  5 days.

That means, average of the 5 heart rate pulse=62

If the last day was 58 and all the other days were the same.

Let x be her pulse on the other days,

Then,

Average, 62=\dfrac{58+4x}{5}\\\text{Cross Multiply}\\58+4x=62 X 5\\\text{Suntract 58 from both sides}\\4x=(62X5)-58\\4x=310-58\\4x=252\\\text{Divide both sides by 4}\\x=63

Her pulse on all the other days is 63.

4 0
2 years ago
What number is between 0.40 and 0.47 it has to be a fraction
Mademuasel [1]
There are an infinite number of possibilities, but one of them could be 45/100 or 9/20
5 0
2 years ago
Read 2 more answers
The net of a triangular prism is shown below. What is the surface area of the prism? A. 128 cm^2 B. 152 cm^2 C. 176 cm^2 D. 304
shtirl [24]

Answer:

B. 152 cm²

Step-by-step explanation:

To find the surface area using a net, do this:

Take apart the figure. We see that there are three rectangles and two triangles. Find the area of each (A=l*w) and then add the values together:

The first rectangle on the left is the same as the one on the right.

5*8=40

Two measures are 40 cm².

The middle rectangle is:

6*8=48

48 cm²

The formula for the area of a triangle is A=\frac{1}{2}*b*h:

A=\frac{1}{2}*6*4\\\\A=\frac{1*6*4}{2}\\\\A=\frac{24}{2}\\\\ A=12

The area of the two triangles is 12 cm².

Now add the values:

40+40+48+12+12=152

The area of the figure is 152 cm².

:Done

4 0
2 years ago
Express x in term of y:x/7+2y=6​
lions [1.4K]

Answer:

You have to multiply the denorminator to both sides in order to make x the subject :

\frac{x}{7 + 2y}  = 6

x = 6(7 + 2y)

8 0
2 years ago
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