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makkiz [27]
1 year ago
9

PLEASE ANSWER FOR POINTS: Which diagram best connects a central Asian country with an important event from its history? A: Armen

ia, was part of the British empire until after the cold war,B: Afghanistan, was part of the British empire through World War 1, C: Kyrgyzstan, fought a war against Azerbaijan in the 1990s,D: Tajikistan, established a policy of permanent neutrality.
Mathematics
1 answer:
xxMikexx [17]1 year ago
4 0

Answer:

Think about it!

Step-by-step explanation:

The human brain is there for a reason. Use it or I'll turn you into a corpse rotting in an alleyway somewhere in Cleveland!

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What is the difference between 76.82 and 2.761
Sophie [7]

74.059 is the answer.




Hope this helps...


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1 year ago
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A shoe manufacture reported earnings of -$453,000 for 2012. In 2013 the company reported earnings of $813,000, and in 2014 the c
vitfil [10]
D $837,000 because your dealing with a negative number. -$453 - 384 = 744 because your still going down in the negatives.<span />
5 0
1 year ago
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From past experience, a company has found that in carton of transistors: 92% contain no defective transistors 3% contain one def
jasenka [17]

Answer:

E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500

In order to find the variance we need to find first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300

The variance is calculated with this formula:

Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075

And the standard deviation is just the square root of the variance and we got:

Sd(X) = \sqrt{0.3075}= 0.5545

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

LEt X the random variable who represent the number of defective transistors. For this case we have the following probability distribution for X

X         0           1           2         3

P(X)    0.92     0.03    0.03     0.02

We can calculate the expected value with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500

In order to find the variance we need to find first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300

The variance is calculated with this formula:

Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075

And the standard deviation is just the square root of the variance and we got:

Sd(X) = \sqrt{0.3075}= 0.5545

8 0
2 years ago
the loudness in decibels of sound is defined as 10 log I/I0, where I is the intensity of the sound in watts per square meter (W/
Oxana [17]
As the problem states, to solve this, we are going to use the equation L= log \frac{I}{I_{0} }
where 
L is the loudness in dB
I is the intensity of a sound 
I_{0}  <span>is the minimum intensity detectable by the human ear
</span>
We know for our problem that I=1.65*10^{-2}; we also now that the minimum intensity detectable by the human ear is 10^{-12)W/m^{2}, so I_{0}=10^{-12}. Lets replace those values in our equation to find L:
L=log \frac{1.65*10^{-2} }{10^{-12}}
L=10.22dB

Qe can conclude that since the explosion is under 100dB, it does not violates the regulation of the town. We used tow physical values to calculate the answer: the intensity of the sound of the explosion, I=1.65*10^{-2}W/m^2, and the minimum intensity detectable by the human ear I_{0}=10^{-12}W/m^{2}.
3 0
2 years ago
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adoni [48]

Answer:

Step-by-step explanation:

Ok I think it is 8 though

4 0
1 year ago
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