We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
Answer:
The following points are not arranged in a parallelogram or rectangle order.
Step-by-step explanation:
Well first we need to graph the following.
A(1,1) B(2,2) C(3,3) D(4,4)
By looking at the image below we can tell it is not any shape, it’s not a parallelogram or a rectangle.
It is a line with a slope of 1 or x.
The value of constant of variation "k" is 
<em><u>Solution:</u></em>
Given that the direct variation is:
y = kx ----- eqn 1
Where "k" is the constant of variation
Given that the point is (5, 8)
<em><u>To find the value of "k" , substitute (x, y) = (5, 8) in eqn 1</u></em>

Thus the value of constant of variation "k" is 