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Tom [10]
2 years ago
5

the loudness in decibels of sound is defined as 10 log I/I0, where I is the intensity of the sound in watts per square meter (W/

m2). I0, the intensity of a barely audible sound, is equal to 10 -12 W/m2. town regulations require the loudness of construction work not to exceed 100 dB. suppose a construction team is blasting rock for a roadway. one explosion has an intensity of 1.65 X 10-2 W/m2. is the explosion in violation of town regulations? which physical value do you need to calculate to answer the question? what values should you use for I and I0
Mathematics
1 answer:
Oxana [17]2 years ago
3 0
As the problem states, to solve this, we are going to use the equation L= log \frac{I}{I_{0} }
where 
L is the loudness in dB
I is the intensity of a sound 
I_{0}  <span>is the minimum intensity detectable by the human ear
</span>
We know for our problem that I=1.65*10^{-2}; we also now that the minimum intensity detectable by the human ear is 10^{-12)W/m^{2}, so I_{0}=10^{-12}. Lets replace those values in our equation to find L:
L=log \frac{1.65*10^{-2} }{10^{-12}}
L=10.22dB

Qe can conclude that since the explosion is under 100dB, it does not violates the regulation of the town. We used tow physical values to calculate the answer: the intensity of the sound of the explosion, I=1.65*10^{-2}W/m^2, and the minimum intensity detectable by the human ear I_{0}=10^{-12}W/m^{2}.
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Step-by-step explanation:

Question:

1) The projections of the legs of a right triangle on the hypotenuse have lengths of 9 cm and 25 cm. Find the length of the height at the top of the right angle.

2) In a right triangle the length of the hypotenuse is 34 cm, and the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75. Calculate the length of the height corresponding to the hypotenuse.

Solution

1) The length of the height of a right angle triangle is also called the altitude.

Since there are no diagrams in the question, I sent a diagram of the right angle as an attachment to the solution.

The projections of the legs are 25cm and 9cm.

Hence, the longer projection length AD = 25cm and the shorter projection length DB = 9cm

In a right triangle, the altitude (height) drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the

geometric mean of these two segments (the two projections) and it's given by:

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There is an error with the figures because the sum of the length of the projection of the legs should be equal to the hypotenuse but it isn't in this case.

To calculate the length of the height corresponding to the hypotenuse, we would use the same formula above.

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34/y = y/9

y^2 = 34×9 = 306

y = √306 = 17.5cm

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