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PolarNik [594]
1 year ago
11

Which phrase best describes the translation from the graph y = 2(x – 15)2 + 3 to the graph of y = 2(x – 11)2 + 3? 4 units to the

left 4 units to the right 8 units to the left 8 units to the right
Mathematics
2 answers:
Mama L [17]1 year ago
8 0
Left is plus right is negative -11-(-15)=4  so you know 4 to the left
ira [324]1 year ago
4 0

we have

y=2(x-15)^{2}+3

this is the equation of a vertical parabola open up with vertex at point (15,3)

y=2(x-11)^{2}+3

this is the equation of a vertical parabola open up with vertex at point (11,3)

so

the rule of the translation is

(x,y)---------> (x-4,y)

that means

the translation is 4 units to the left

therefore

<u>the answer is</u>

4 units to the left

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What values of b satisfy 3(2b + 3)2 = 36?
meriva
What values of b satisfy 3(2b+3)^2 = 36

we have
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
take the square root of both sides
( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3

b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}

b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
therefore

the answer is
the values of b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
9 0
1 year ago
Your model locomotive is 16 inches long. It is an exact model of a locomotive that is 40 feet long. A window on the locomotive i
Ierofanga [76]
1 feet is 12 inches so 40 feets is 480 inches
Real locomotive is 480/16=30 times wider then the model
And then a window on the real locomotive is 30 times wider then the model.
7 0
2 years ago
Zula has a conical bird feeder with a volume of 64.3 cubic centimeters and a height of 7 centimeters. Which equation can be used
Ulleksa [173]

Answer:

16.075 is the answer.

Step-by-step explanation:

16.075 is the answer. I hope this helps. You divide

64.3/7

=16.075

6 0
2 years ago
Read 2 more answers
Andy got a 32% discount on all his purchases at his favorite shop. If he saved $64 on the total bill, the bill amount without th
Julli [10]
$200 without the discount and he payed $136.
7 0
1 year ago
A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame
snow_tiger [21]

Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

Therefore,  length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be =  (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame -  area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

 3500 = (2x+50) * (2x+70) - 3500.

Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

Applying quadratic formula =\frac{-b\pm \sqrt{b^2-4ac}}{2a}, we get

=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

We could take approximately 12 cm.



7 0
2 years ago
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