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2 years ago

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Which phrase best describes the translation from the graph y = 2(x – 15)2 + 3 to the graph of y = 2(x – 11)2 + 3? 4 units to the

left 4 units to the right 8 units to the left 8 units to the right

2 answers:

Mama L [17]2 years ago

8 0

Left is plus right is negative -11-(-15)=4 so you know 4 to the left

ira [324]2 years ago

4 0

we have

$y=2(x-15)^{2}+3$

this is the equation of a vertical parabola open up with vertex at point $(15,3)$

$y=2(x-11)^{2}+3$

this is the equation of a vertical parabola open up with vertex at point $(11,3)$

so

the rule of the translation is

$(x,y)---------> (x-4,y)$

that means

the translation is $4$ units to the left

therefore

<u>the answer is</u>

$4$ units to the left

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2 years ago

The number of hours Layla worked each week for the first eight weeks of summer break are recorded below.

Rainbow [258]

Answer: The value of the center increases and the distribution has a smaller spread.

Step-by-step explanation:

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12 ,14, 16 , 19, 21 , 22 , 28 , 32

Median = 19 + 21 / 2

= 40/2

= 20

Also calculating the standard variation in order to know the spread , we need to first of all calculate the mean

Mean = 12 + 14 + 16 + 19 + 21 + 22 + 28 + 32 / 8

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Therefore to calculate the standard deviation, we need to calculate the variance, which is

$(12-20.5)^{2}$ + $(14-20.5)^{2}$ + $(16-20.5)^{2}$ + $(19-20.5)^{2}$ + $(21-20.5)^{2}$ + $(22-20.5)^{2}$ + $(28-20.5)^{2}$ + $(32-20.5)^{2}$ / 8

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S.D = $\sqrt{41}$

S.D = 6.4

Also re arranging the second values , we have :

20 , 24 , 25 , 31

Median = 24 + 25 / 2

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8 0

2 years ago

Read 2 more answers

Consider the initial value problem y′+4y=48t,y(0)=9. y′+4y=48t,y(0)=9. Take the Laplace transform of both sides of the given dif

Nadusha1986 [10]

Answer:

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Step-by-step explanation:

given is the Differential equation in I order linear as

$y′+4y=48t,y(0)=9.$

Take Laplace on both sides

$L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}$

Now if we take inverse we get y(t) the solution

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8 0

2 years ago

Is it possible to form a triangle with side lengths 3.5 3.5, and 9? If so, will it be scalene, isosceles, or equilateral? Or non

Charra [1.4K]

Answer:

It is not possible to draw a triangle with given measurements of 3.5, 3.5, and 9.

Step-by-step explanation:

<em><u>Scalene Triangle</u></em> - All 3 sides have different lengths.

<em><u>I</u></em><em><u>s</u></em><em><u>osceles</u></em><em><u> </u></em><em><u>Triangle</u></em> - 2 sides have equal lengths.

<em><u>Equilateral</u></em><em><u> </u></em><em><u>Triangle</u></em> - All 3 sides have equal lengths.

You must be thinking that it would be Isosceles triangle, but it is not. The measurements you gave is 3.5, 3.5, and 9. Grab a piece of paper, ruler, and a pencil. First draw the length of 9 cm with your pencil and ruler (let us pretend that the measurements are in cm). Then draw 3.5 cm by placing your ruler on the end/start of your 9cm line that you drew before. Then, once again draw a 3.5 cm on the other end of the 9cm line. You will see something like the picture above. You can see that the two sides of the triangle are not intersecting on the top. This means that the triangle formation cannot be made by the given measurements of 3.5, 3.5, and 9.

I hope you understand my answer and this is an easy way to find if, from the given measurements, a triangle is able to be drawn. Thank you !!

4 0

2 years ago

Nimfa-mama [501]

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and ...................................................Gauri = 60/12 = 5,

and .....................................................Yasmin = 60/20 = 3.

3 0

2 years ago