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1 year ago

A car travels 180 miles in 4 hours. Find the car’s speed in feet per minute. (There are 5,280 ft in 1 mile)

Mathematics

1 answer:

FinnZ [79.3K]1 year ago

4 0

Given :

Distance travelled , d = 180 miles.

Time taken , t = 4 hours.

To Find :

Speed in feet per minutes.

Solution :

Distance in feet is , d = 180×5280 = 950400 feet.

Time taken , t = 4×60 = 240 minutes.

Speed is given by , $s=\dfrac{Distance}{Time \ Taken}$

$S=\dfrac{950400}{240}\ ft/min\\\\S=3960\ ft/min$

Hence, this is the required solution.

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Barbara sells iced tea for $1.49 per bottle and water for $1.25 per bottle. She wrote an equation to find the number of drinks s

Oksana_A [137]

The way she put it implies that she will sell many water bottles and only one iced tea. the correct equation would be 1.25x+1.49y=100, as she may sell different amounts of each.

4 0

1 year ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

bezimeni [28]

Answer:

Part 1) $A(57/7,9),B(4,16/5), m=7/5$

Part 2) $A(-7,6),B(9,-6/7), m=-3/7$

Part 3) $A(80/3,9),B(5,2.5), m=0.3$

Part 4) $A(-10/63,1/3),B(2/3,-22/90), m=-0.7$

Part 5) $A(-1/5,7),B(8,48), m=5$

Step-by-step explanation:

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept

Part 1) we have

$7x-5y=12$

step 1

Find the slope

$7x-5y=12$

isolate the variable y

$y=(7/5)x-(12/5)$

the slope is $m=(7/5)$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$9=(7/5)x-(12/5)$

$(7/5)x=9+(12/5)$

$(7/5)x=(57/5)$

$x=(57/7)$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=(7/5)(4)-(12/5)$

$y=(28/5)-(12/5)$

$y=(16/5)$

Part 2) we have

$y=-(3/7)x+3$

step 1

Find the slope

the slope is $m=-(3/7)$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$6=-(3/7)x+3$

$(3/7)x=3-6$

$(3/7)x=-3$

$x=-7$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=-(3/7)(9)+3$

$y=-(27/7)+3$

$y=-(6/7)$

Part 3) we have

$y=0.3x+1$

step 1

Find the slope

the slope is $m=0.3$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$9=0.3x+1$

$0.3x=9-1$

$0.3x=8$

$x=80/3$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=0.3(5)+1$

$y=2.5$

Part 4) we have

$6.3x+9y=2$

step 1

Find the slope

$6.3x+9y=2$

isolate the variable y

$y=-(0.7)x+(2/9)$

the slope is $m=-0.7$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$(1/3)=-(0.7)x+(2/9)$

$(0.7)x=(2/9)-(1/3)$

$(0.7)x=-(1/9)$

$x=-(10/63)$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=-(0.7)(2/3)+(2/9)$

$y=-(14/30)+(2/9)$

$y=-(22/90)$

Part 5) we have

$y-5x=8$

step 1

Find the slope

$y-5x=8$ -------> $y=5x+8$

the slope is $m=5$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$7=5x+8$

$5x=7-8$

$x=-1/5$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=5(8)+8$

$y=48$

6 0

2 years ago

A manufacturer is designing a flashlight. For the flashlight to emit a focused beam, the bulb needs to be on the central axis of

aalyn [17]

From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12

Source:
http://www.1728.org/quadr4.htm