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2 years ago

Pentagon ABCDE was enlarged:

Mathematics

1 answer:

enot [183]2 years ago

7 0

Answer/Step-by-step explanation:

The ratio of the enlargement to the original = A'E' to AE = A'E':AE = A'E'/AE

AE = 2.5

A'E' = 4

Ratio of the enlargement to the original = 4:2.5 = 1.6:1

To convert to percentage, divide 4 by 2.5 and multiply by 100.

$= \frac{4}{2.5}*100$

$= 1.6*100$

$= 160 percent$

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Suppose the supply function for product x is given by qxs = - 30 + 2px - 4pz.

Igoryamba

It is given in the question that

Suppose the supply function for product x is given by

$qxs = - 30 + 2px - 4pz.$

And we have to find how much of product x is produced when px = $600 and pz = $60.

And for that, we have to substitute 600 for px and 60 for pz, and on doing so, we will get

$qxs = -30+2(600)-4(60)
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2 years ago

Which of the following is equivalent to the complex number i^{6}

Helga [31]

$\bf \textit{recall that }i^2=-1
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2 years ago

Read 2 more answers

Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised t

zimovet [89]

Answer:

(b) 1/792

Step-by-step explanation:

The complete question is;

Counting: Grading One professor grades homework by randomly choosing 5 out of 12 homework problems to grade.

(a) How many different groups of 5 problems can be chosen from the 12

problems?

(b)Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised the group that was selected to be graded?

In (a)

Apply the formula

$\frac{n!}{(n-r)!(r!)}$

where n=12 and r=5

substitute values

$=\frac{12!}{(12-5)!(5!)} \\\\\\=\frac{12!}{(7!)(5!)} \\\\\\=\frac{12*11*10*9*8}{5*4*3*2*1} \\\\\\=\frac{95040}{120} \\\\\\=792$

In (b)

If Jerry did only 5 problems of one assignment then the probability will be

$\frac{5}{12} *\frac{4}{11} *\frac{3}{10} *\frac{2}{9} *\frac{1}{8} =\frac{1}{792}$

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2 years ago

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loris [4]

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2 years ago

An agency that hires out clerical workers claims its workers can type, on average, at least 60 words per minute (wpmwpm). To tes

lapo4ka [179]

Answer:

The right answer is:

If the mean typing speed of workers from the agency is 60 wpmwpm, the probability of selecting a sample of 50 workers with mean 58.8 wpmwpm or less is 0.267.

Step-by-step explanation:

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If the P-value is low enough, that is under the significance level, then we can infer that the mean that the null hypothesis states is not the actual mean, and we have evidence to reject the null hypothesis.

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