If G is midpoint of FH, find FG

In ΔSTU, the measure of ∠U=90°, TU = 6.6 feet, and US = 2.3 feet. Find the measure of ∠S to the nearest tenth of a degree.

zimovet [89]

Answer:

70.8°

Step-by-step explanation:

The sides and angles are related in a right triangle such that ...

Tan = Opposite/Adjacent

tan(S) = UT/US = 6.6/2.3

The inverse tangent function is used to find the angle from its value:

∠S = arctan(6.6/23)

∠S ≈ 70.8°

8 0

2 years ago

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Two fifths of the square of the number j in algebraic exprission

Tomtit [17]

Two-fifths ( $\frac{2}{5}$ ) of the square of the number j (j²)

$\frac{2}{5}$ j²

5 0

2 years ago

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Find the value of the linear correlation coefficient r. The paired data below consist of the temperatures on randomly chosen day

n200080 [17]

Answer:

n=9 $\sum x = 530, \sum y = 243, \sum xy = 14615, \sum x^2 =32656, \sum y^2 =8245$

And replacing the info we got:

$r=\frac{9(14615)-(530)(243)}{\sqrt{[9(32656) -(530)^2][9(8245) -(243)^2]}}=0.1955$

So then the correlation coefficient would be r =0.1955

Step-by-step explanation:

Data given

Temperature (x) 62 76 50 51 71 46 51 44 79

Growth (y) 36 39 50 13 33 33 17 6 16

Solution

The correlation formula is given by:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have the following sums:

n=9 $\sum x = 530, \sum y = 243, \sum xy = 14615, \sum x^2 =32656, \sum y^2 =8245$

And replacing the info we got:

$r=\frac{9(14615)-(530)(243)}{\sqrt{[9(32656) -(530)^2][9(8245) -(243)^2]}}=0.1955$

So then the correlation coefficient would be r =0.1955

6 0

2 years ago

The density of an object can be found by taking its mass and dividing by its volume. Write an equation to represent the relation

prisoha [69]

Answer:

Step-by-step explanation:

The density of an object can be found by taking its mass and dividing by its volume.

Hence if density is D , Mass is M and Volume is V

$D=\frac{M}{V}$

a)

M = 500 gms

V = 40 cubic cm

$D=\frac{500}{40}$

$D=12.5$

b)

M = 125 gms

V = 1.4 cubic cm

$D=\frac{125}{1.4}$

$D=89.28$

D =89.28 gm per cc

3 0

2 years ago

Blue's Berry Farm charges Percy a total of

kaheart [24]

Answer:

The price for each kilogram of strawberries is $7.50

Step-by-step explanation:

<u><em>The question is</em></u>

Blues berry farm charges Percy a total of $24.75 for entrance and 2.5 kilograms of strawberries. The entrance fee is $6 and the price for each kilogram of strawberries is constant

Determine the price for each kilogram of strawberries

Let

x ----> the price for each kilogram of strawberries

we know that

The entrance fee plus the price of each kilogram of strawberries multiplied by the number of kilogram of strawberries must be equal to $24.75

so

The linear equation that represent this situation is

$2.5x+6=24.75$

solve for x

subtract 6 both sides

$2.5x=24.75-6\\2.5x=18.75$

divide by 2.5 both sides

$x=\$7.50$

therefore

The price for each kilogram of strawberries is $7.50

8 0

2 years ago