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cricket20 [7]
2 years ago
12

Luis made some trail mix .He mixed 4 2/3 cups of popcorn ,1 1/4 cups of peanuts ,1 1/3 cups of raisins ,and 3/4 cup of sunflower

seeds.He gave 5 of his friends an equal amount of trail mix each.How much did each friend get?

Mathematics
1 answer:
erastova [34]2 years ago
4 0
I would say the answer is A.
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The height of a cylinder is twice the radius of its base. A cylinder has a height of 2 x and a radius of x. What expression repr
mrs_skeptik [129]

<u>Given</u>:

Let x represents the radius of the cylinder.

Given that the height of the cylinder is twice the radius of its base.

The height of the cylinder is 2x.

We need to determine the volume of the cylinder.

<u>Volume of the cylinder:</u>

The volume of the cylinder can be determined using the formula,

V=\pi r^2h

Substituting r = x and h = 2x, we get;

V=\pi (x)^2(2x)

Simplifying, we get;

V=\pi x^2(2x)

V=2\pi x^3

Thus, the expression that represents the volume of the cylinder is 2πx³ cubic units.

Hence, Option b is the correct answer.

8 0
2 years ago
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An exponential function and a quadratic function are graphed below. Which of the following is true of the growth rate of the fun
aleksley [76]
Given an exponential function, say f(x), such that f(0) = 1 and f(1) = 2 and a quadratic finction, say g(x), such that g(0) = 0 and g(1) = 1.

The rate of change of a function f(x) over an interval
a \leq x \leq b
is given by
\frac{f(b)-f(a)}{b-a}

Thus, the rate of change (growth rate) of the exponential function, f(x) over the interval
0 \leq x \leq 1
is given by
\frac{f(1)-f(0)}{1-0} = \frac{2-1}{1} =1

Similarly, the rate of change (growth rate) of the quadratic function, g(x) over the interval
0 \leq x \leq 1
is given by
\frac{g(1)-g(0)}{1-0} = \frac{1-0}{1} =1

Therefore, the exponential grows at the same rate as the quadratic in the interval <span>0 \leq x \leq 1.</span>
3 0
2 years ago
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Find the absolute maximum and absolute minimum of the function f(x,y)=2x2−4x+y2−4y+1 on the closed triangular plate bounded by t
marusya05 [52]

First check for the critical points of <em>f</em> by checking where the first-order derivatives vanish.

\dfrac{\partial f}{\partial x}=4x-4=0\implies x=1

\dfrac{\partial f}{\partial y}=2y-4=0\implies y=2

Notice how the point (1, 2) lies on the line <em>y</em> = 2<em>x</em> ; at this point, we get a value of <em>f</em>(1, 2) = -5 (MIN).

Next, check the points where the boundary lines intersect, which occurs at the points (0, 0), (0, 2), and (1, 2). We already checked the last one. We find <em>f</em>(0, 0) = 1 (MAX) and <em>f</em>(0, 2) = -3.

Now check on the boundary lines themselves. If <em>x</em> = 0, then

f(0,y)=y^2-4y+1=(y-2)^2-3

which has a maximum value of -3 when <em>y</em> = 2 (so we get the same critical point as before).

If <em>y</em> = 2, then

f(x, 2)=2x^2-4x-3=2(x-1)^2-5

with a maximum of -5 when <em>x</em> = 1.

If <em>y</em> = 2<em>x</em>, then

f(x,2x)=6x^2-12x+1=6(x-1)^2-5

with the same maximum of -5 when <em>x</em> = 1.

6 0
2 years ago
An elevator starts at the 6th floor. It goes up 7 floors twice, and then it goes
seraphim [82]
The second

6+(7×2)-10 = 10
20-(5×3)+12 = 17
4 0
2 years ago
Read 2 more answers
Total employment for sheet metal workers in 2016 is projected to be 201,000. if this is a 6.3% increase from 2006, approximately
fomenos

Answer:

Option d.

Step-by-step explanation:

Total employment for sheet metal workers in 2016 is projected to be = 201,000

This is a 6.3% increase from 2006.

Let the number of workers in 2006 be n

n + (6.3% of n) = 201,000

n + ( 0.063n) = 201,000

1.063n = 201,000

n = \frac{201,000}{1.063}

n = 189,087. 4882 ≈ 189,000

the total employment in 2006 was approximately 189,000

Option d is the answer.

8 0
2 years ago
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