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Natali [406]
2 years ago
6

Mean Height of Men A formal hypothesis test is to be conducted using the claim that the mean height of men is equal to 174.1 cm.

What is the null hypothesis, and how is it denoted? What is the alternative hypothesis, and how is it denoted? What are the possible conclusions that can be made about the null hypothesis? Is it possible to conclude that "there is sufficient evidence to support the claim that the mean height of men is equal to 174.1 cm"?

Mathematics
1 answer:
viktelen [127]2 years ago
4 0

Answer: kindly check explanation

Step-by-step explanation:

The Null hypothesis says mean height is 174.1cm

The alternative hypothesis negatea the null hypothesis :

Possible conclusions that can be made about the Null hypothesis. After utilizing the tbe various statistical procedures, we can either stand by the Null hypothesis or we reje t this null Hypothesis.

From the question above, supporting tbe claim that the mean height of men is equal to 174.1 cm is impossible as the expression represents the null claim. Statistical test are only used to support an alternative claim whereby if the test is not significant at certain level of significance x

Alternative hypothesis serves as the claim which requires statistical test on other to establish it's significance.

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Step-by-step explanation:

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Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Step-by-step explanation:

\text{The equation for ball height} : 6+30\cdot t-16\cdot t^{2}\\\text{The equation for shot blocker's height} : 9+25\cdot t-16\cdot t^{2}

But, the shot is made before two tenths of a second or 0.2 seconds therefore modified equation for ball height is :

6+30\cdot (t-0.2)-16\cdot (t-0.2)^{2}

Now for the shot to be blocked,the height of shot blocker must be greater than the height of the ball which is shot before 0.2 seconds :

\implies 9+25\cdot t-16\cdot t^{2}\geq 6+30\cdot (t-0.2)-16\cdot (t-0.2)^{2}\\\implies 9+25\cdot t-16\cdot t^{2}\geq 6+30\cdot t-6-16\cdot (t^{2}-0.4\cdot t+0.04)\\\implies9+25\cdot t-16\cdot t^{2}\geq 30\cdot t-16\cdot t^{2}+6.4\cdot t-0.64\\\implies 9+25\cdot t\geq 36.4\cdot t-0.64\\\implies 9.64\geq 11.4\cdot t\\\\\implies t\leq \frac{9.64}{11.4}\approx 0.846

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Step-by-step explanation:

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Answer:

D. x-\frac{5}{2}y =  \frac{25}{2}

Step-by-step explanation:

Given

y = \frac{2}{5}x - 5

Required

Determine its equivalent

<em>From the list of given options, the correct answer is</em>

x - \frac{5}{2}y = \frac{25}{2}

This is shown as follows;

y = \frac{2}{5}x - 5

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\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)

Open Bracket

\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5

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Subtract x from both sides

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Multiply both sides by -1

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Reorder

x-\frac{5}{2}y =  \frac{25}{2}

<em>Hence, the correct option is D</em>

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