Question

A student measured the specific heat of water to be 4.29 J/gC. The literature value of the specific heat of water is 4.18J/gC. Hey What was the students percent error?

Answer 1

Answer:

2.44 %

Explanation:

Given that,

The calculated value of specific heat of water to be 4.29 J/g°C

The actual value of the specific heat of water is 4.18J/g°C

We need to find the percentage error of the student

$\text{Percentage error}=\dfrac{|\text{actual value-calculated value}|}{\text{actual value}}\times 100\\\\\%=\dfrac{4.18-4.29}{4.49}\times 100\\\\\%=2.44$

Hence, the student's percent error is 2.44 %.