All categories

2 years ago

(x³-3x²+2x+1/x²-4x+4)dx(dx/Dy)+(x²+4y-y²)/(²√4y+y²) solve for dx/dy

Mathematics

1 answer:

Furkat [3]2 years ago

4 0

It’s 22/3 I think so that’s the answer

You might be interested in

As a smart consumer, you are always on the lookout for sales, coupons, and rebates. While shopping for new clothes, you notice t

Firlakuza [10]

Answer:

You'd have to buy 3 shirts in order to use your coupon.

Step-by-step explanation:

Each shirt originally costs $17.99

One particular brand of shirts is on sale for 20% off the original price.

$17.99*0.2= $3.60 (amount taken off for each shirt)

Now subtract $3.60 from $17.99.

$17.99 - $3.60 = $14.39 (per shirt)

40 / 14.39 = 2.779 (round to 3)

You'd have to buy 3 shirts in order to use your coupon.

$14.39 * 3 = $43.17, in order to get $10 off you'd need to spend at least $40

7 0

2 years ago

Solve the system using elimanation: 5x + 4y = 12. 3x -3y = 18

Scorpion4ik [409]

If you would like to solve the system of equations 5x + 4y = 12 and 3x - 3y = 18 using elimination, you can do this using the following steps:

<span>5x + 4y = 12 /*3
3x - 3y = 18 /*4
_____________
15x + 12y = 36
12x - 12y = 72
_____________
15x + 12y + 12x - 12y = 36 + 72
15x + 12x = 36 + 72
27x = 108
x = 108/27
x = 4

</span><span>3x - 3y = 18
</span>3 * 4 - 3y = 18
12 - 3y = 18
12 - 18 = 3y
3y = -6
y = -6/3
y = -2

(x, y) = (4, -2)

The correct result would be: x = 4 and y = -2.

4 0

2 years ago

Read 2 more answers

Jeff hiked for 2 hours and traveled 5 miles. If he continues at the same pace, which equation will show the relationship between

Lady_Fox [76]

Answer: The relationship between distance and time is $d=2.5t$ and the graph is continuous.

Step-by-step explanation:

Since we have given that

Number of hours he hiked = 2 hours

Distance covered = 5 miles

Speed would be

$\dfrac{Distance}{Time}\\\\=\dfrac{5}{2}\\\\=2.5\ mph$

Let the distance be 'd'.

Let the time be 't'.

so, the relation between distance and time would be

$distance=Speed\times time\\\\d=2.5t$

The graph is continuous because it is not based on counts and the points are connected with a continuous line without any break.

Hence, the relationship between distance and time is $d=2.5t$ and the graph is continuous.

3 0

2 years ago

Read 2 more answers

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

6 0

2 years ago

Find the sum of the first 30 terms of the sequence below an=3n+2

Solnce55 [7]

First off, let's find the 1st term's value, and the 30th term's value,

$\bf a1=3(1)+2\implies a1=5\qquad \qquad \quad a30=3(30)+2\implies a30=92\\\\
-------------------------------\\\\
~~~~~~~\textit{ Sum of an arithmetic sequence}\\\\
S_n=\cfrac{n(a1+an)}{2}~ 
\begin{cases}
n=n^{th}\ term\\
a1=\textit{first term's value}\\
----------\\
a1=5\\
a30=92\\
n=30
\end{cases} \implies S_{30}=\cfrac{30(5+92)}{2}
\\\\\\
S_{30}=15(97)$

6 0

2 years ago

Read 2 more answers

(x³-3x²+2x+1/x²-4x+4)dx(dx/Dy)+(x²+4y-y²)/(²√4y+y²) solve for dx/dy​

(x³-3x²+2x+1/x²-4x+4)dx(dx/Dy)+(x²+4y-y²)/(²√4y+y²) solve for dx/dy