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Alisiya [41]
2 years ago
6

A local hamburger shop sold a combined total of 685 hamburgers and cheeseburgers on Wednesday. There were 65 fewer cheeseburgers

sold than hamburgers. How many hamburgers were sold on Wednesday?
Mathematics
1 answer:
noname [10]2 years ago
8 0

Answer:

620

Step-by-step explanation:

I might be wrong.

But based on the question both burgers are sold on a Wednesday so the question is asking how many cheeseburgers were sold on a Wednesday (which is the same day they both were sold) so I think you subtract.

so 685-65.

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Answer: (-4,-8)

Step-by-step explanation: I got a 100% on the quiz

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Triangles A B C and X Y Z are shown. Which would prove that ΔABC ~ ΔXYZ? Select two options. StartFraction B A Over Y X = StartF
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Answer: Answer is 3

BC        6

------ = ------

XY         3

Step-by-step explanation:

The statements below can be used to prove that the triangles are similar.

On a coordinate plane, right triangles A B C and X Y Z are shown. Y Z is 3 units long and B C is 6 units long.  

A B Over X Y = 4 Over 2

?  

A C Over X Z = 52 Over 13  

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Which mathematical statement is missing?

1.   Y Z Over B C = 6 Over 3  

2.  ∠B ≅ ∠Y

3.  B C Over Y Z = 6 Over 3  

4.  ∠B ≅ ∠Z

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2 years ago
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the vertex form of a function is g(x) = (x – 3)2 9. how does the graph of g(x) compare to the graph of the function f(x) = x2? g
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(b) For those values of k, verify that every member of the family of functions y = A sin(kt) + B cos(kt) is also a solution. y =
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Answer:

Check attachment for complete question

Step-by-step explanation:

Given that,

y=Coskt

We are looking for value of k, that satisfies 4y''=-25y

Let find y' and y''

y=Coskt

y'=-kSinkt

y''=-k²Coskt

Then, applying this 4y'"=-25y

4(-k²Coskt)=-25Coskt

-4k²Coskt=-25Coskt

Divide through by Coskt and we assume Coskt is not equal to zero

-4k²=-25

k²=-25/-4

k²=25/4

Then, k=√(25/4)

k= ± 5/2

b. Let assume we want to use this

y=ASinkt+BCoskt

Since k= ± 5/2

y=A•Sin(±5/2t)+ B •Cos(±5/2t)

y'=±5/2ACos(±5/2t)-±5/2BSin(±5/2t)

y''=-25/4ASin(±5/2t)-25/4BCos(±5/2t

Then, inserting this to our equation given to check if it a solution to y=ASinkt+BCoskt

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For 4y''

4(-25/4ASin(±5/2t)-25/4BCos(±5/2t))

-25A•Sin(±5/2t)-25B•Cos(±5/2t).

Then,

-25y

-25(A•Sin(±5/2t)+ B •Cos(±5/2t))

-25A•Sin(±5/2t) - 25B •Cos(±5/2t)

Then, we notice that, 4y'' is equal to -25y, then we can say that y=Coskt is a solution to y=ASinkt+BCoskt

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Y=mx + b
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