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MArishka [77]
2 years ago
3

How many electrons are there in the “p” orbitals of the last shell (principal energy level) of silicon, atomic number 14?

Chemistry
1 answer:
LekaFEV [45]2 years ago
3 0
The P orbital of silicon has 6 electrons
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How many moles of cacl2 are in 250 ml of a 3.0 m of cacl2 solution?
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The last option, "Energy that flows from a hot mug of tea to a cold hand." Hope this helps!

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2 years ago
What is the number of moles of <br> 0.0960g of H2SO4
Vilka [71]
<span>Answer</span>=.000978802802moles H2SO4

How I Got My Answer

<span>Molar mass 
</span>H2SO4= 98.079g/mol

What I have
.0960g H2SO4

Equation
.0960g*1mol/98.079g= .000978802802mol H2SO4


5 0
2 years ago
You mix 500.0 mL of 0.250 M iron(III) chloride solution with 425.0 mL of 0.350 M barium chloride solution. Assuming the volumes
12345 [234]

Answer:

M=0.727M

Explanation:

Hello,

In this case, since iron (III) chloride (FeCl3) and barium chloride (BaCl2) are both chloride-containing compounds, we can compute the moles of chloride from each salt, considering the concentration and volume of the given solutions, and using the mole ratio that is 1:3 and 1:2 for the compound to chlorine:

n_{Cl^-}=0.50L*0.250\frac{molFeCl_3}{L}*\frac{3molCl^-}{1molFeCl_3}=0.375molCl^-  \\\\n_{Cl^-}=0.425L*0.350\frac{molBaCl_2}{L}*\frac{2molCl^-}{1molBaCl_2}=0.2975molCl^-

So the total mole of chloride ions:

N_{Cl^-}=0.2975mol+0.375mol=0.6725molCl^-

And the total volume by adding the volume of each solution in L:

V=0.500L+0.425L=0.925L

Finally, the molarity turns out:

M=\frac{0.6725molCl^-}{0.925L}\\ \\M=0.727M

Best regards.

5 0
2 years ago
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